Since the mole ratio is 1 to 1 for this reaction, you can just use M1V1 = M2V2 to solve, given that 1 refers to HBr and 2 refers to LiOH.
M1 = ?
V1 = 0.40 L
M2 = 0.50 M
V2 = 0.20 L
M1(0.40) = (0.50)(0.20)
Solve for M1 —> M1 = (0.50)(0.20)/0.40 = 0.25 M HBr
If you have to write<span> the chemical </span>formula<span> of a simple, binary ionic compound given the name of the compound, you follow a set of three steps. Let's go through them using magnesium chloride as an example. </span>Write<span> the symbols for the cation and the anion: Mg and Cl. Determine the charge on the cation and anion.</span>
Answer:
if you tell me how much is needed and how much you have then i can answer it, but there is not enough information provided to answer to that question.
Explanation:
The cell notation is:
here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell
in anodic half cell : oxidation takes place [loss of electrons]
in cathodic half cell: reduction takes place [gain of electrons]
1) this is a galvanic cell
2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode
Therefore
3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative
Δ
As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.
Answer is: sodium fluoride NaF.
Sodium fluoride hydrolyse on strong base sodium hydroxide (NaOH) and weak acid hydrofluoric acid (HF), so water solution has pH greater that seven ant it is basic. Other salts have neutral or acidic pH value in water, because they hydrolyse on strong acid and weak or strong base.
