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slavikrds [6]
3 years ago
5

The slope is -1: (-4, -1)

Mathematics
1 answer:
IceJOKER [234]3 years ago
3 0

Answer:

4 is the best answer for it

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If the acceleration of an object is given by dv/dt = −2v, Find the position function s(t) if v(0) = 7 and s(0) = 0.
kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence lnv = -2t+ln 7\\v=7e^{-2t}

since velocity is rate of change of distance s we have

v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[

substitute t=0 and s=0

C=7/2

So solution for distance is

s(t) =\frac{-7}{2} (e^{-2t}-1)

4 0
3 years ago
The Thompson family is buying a car that can travel 70 miles
gogolik [260]

Answer:

The car gets 35 miles per gallons.

Step-by-step explanation:

4 0
3 years ago
In order to solve the following system of equations by addition, which of the
Pavlova-9 [17]

Answer:

Multiply the top equation by -3 and the bottom equation by 2

Step-by-step explanation:

Given <u>system of equations</u>:

\begin{cases}4x-2y=7\\3x-3y=15 \end{cases}

To solve the given system of equations by addition, make one of the variables in both equations <u>sum to zero</u>.  To do this, the chosen variable must have the <u>same coefficient</u>, but it should be <u>negative</u> in one equation and <u>positive</u> in the other, so that when the two equations are added together, the variable is <u>eliminated</u>.

<u>To eliminate the </u><u>variable y</u>:

Multiply the top equation by -3 to make the coefficient of the y variable 6:

\implies -3(4x-2y=7) \implies -12x+6y=-21

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

\implies 2(3x-3y=15) \implies 6x-6y=30

Add the two equations together to <u>eliminate y</u>:

\begin{array}{l r r}& -12x+6y= &-21\\+ & 6x-6y= & 30\\\cline{1-3}& -6x\phantom{))))))} = & 9\end{array}

<u>Solve</u> for x:

\implies -6x=9

\implies x=-\dfrac{9}{6}=-\dfrac{3}{2}

<u>Substitute</u> the found value of x into one of the equations and <u>solve for y</u>:

\implies 3\left(-\dfrac{3}{2}\right)-3y=15

\implies -\dfrac{9}{2}-3y=15

\implies -3y=\dfrac{39}{2}

\implies y=-\dfrac{39}{2 \cdot 3}

\implies y=-\dfrac{13}{2}

Learn more about systems of equations here:

brainly.com/question/27868564

brainly.com/question/27520807

3 0
2 years ago
Read 2 more answers
A theatre group sold a total of 440 tickets for a show, making a total of $3940. Each regular ticket cost $5, each premium ticke
valentina_108 [34]

Answer: 330 regular tickets, 46 premium tickets and 64 elite tickets were sold.

Step-by-step explanation:

Let x represent the number of regular tickets that were sold.

Let y represent the number of premium tickets that were sold.

Let z represent the number of elite tickets that were sold.

The theatre group sold a total of 440 tickets for the show. It means that

x + y + z = 440- - - - - - - - - -1

Each regular ticket cost $5, each premium ticket cost $15, and each elite ticket cost $25. The total amount made from the show was $3940. It means that

5x + 15y + 25z = 3940- - - - - - - - - 2

The number of regular tickets was three times the number of premium and elite tickets combined. It means that

x = 3(y + z)

x = 3y + 3z

Substituting x = 3y + 3z into equation 1 and equation 2, it becomes

3y + 3z + y + z = 440

4y + 4z = 440- - - - - - - - - - - - -3

5(3y + 3z) + 15y + 25z = 3940

15y + 15z + 15y + 25z = 3940

30y + 40z = 3940 - - - - - - - - - - 4

Multiplying equation 3 by 10 and equation 4 by 1, it becomes

40y + 40z = 4400

30y + 40z = 3940

Subtracting, it becomes

10y = 460

y = 460/10

y = 46

Substituting y = 46 into equation 3, it becomes

4 × 46 + 4z = 440

184 + 4z = 440

4z = 440 - 184

4z = 256

z = 256/4

z = 64

x = 3(y + z) = 3(46 + 64)

x = 330

4 0
3 years ago
Can someone help me out
LiRa [457]

3/196

Step-by-step explanation:

multiply everything

5 0
3 years ago
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