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meriva
2 years ago
9

What is the solution to the system of linear equations graphed below? On a coordinate plane, 2 lines intersect at (3.5, negative

4). (3 and one-half, negative 4) (Negative 4, 3 and one-half) (0, 3) (0, negative 4)
Mathematics
2 answers:
Katen [24]2 years ago
3 0

Answer:

Step-by-step explanation:

the answer is C just did the quiz

harkovskaia [24]2 years ago
3 0

Answer:

its D i got it right on edge if there are any probs just tell me and i ll edit mark me brainleiest and hart and five stars please

Step-by-step explanation:

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Which pair of angles are supplementary? ​
PolarNik [594]

Answer: H

Step-by-step explanation:

Supplementary angles just mean they add up to 180 degrees. 180 degrees means that when the two angles are put together one of each of their sides will form a straight line.

6 0
3 years ago
Write an equation of a circle with a center at (2, - 4) and a radius of 4.
fgiga [73]

9514 1404 393

Answer:

  (x -2)^2 +(y +4)^2 = 16

Step-by-step explanation:

The equation of a circle with center (h, k) and radius r is ...

  (x -h)^2 +(y -k)^2 = r^2

You have (h, k) = (2, -4) and r = 4, so your equation is ...

  (x -2)^2 +(y -(-4))^2 = 4^2

  (x -2)^2 +(y +4)^2 = 16

6 0
3 years ago
Simplify the expression
Charra [1.4K]

Answer:−28−98i

Step-by-step explanation:

8 0
3 years ago
Pls help! given: -2(x-4)=2x+12 Prove: x=-1
nata0808 [166]

Answer:

X= -1

Step-by-step explanation:

In pic

(hope this helps can I pls have brainlist (crown) ☺️)

7 0
3 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
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