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forsale [732]
3 years ago
7

Mass of 1 mole of electron in grams is 5.5*10^-4 , how?

Chemistry
1 answer:
Sever21 [200]3 years ago
7 0

Explanation:

Mass of an electron =9.1×10−28g

∴ mass of one mole

=9.1×10−28×6.02×1023

=54.78×10−4g

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If 3.0 g of NH3 reacts with 5.0 g of HCl, what is the limiting reactant?
ELEN [110]
<h2>Answer:HCl</h2>

Explanation:

\text{number of moles}=\frac{\text{given mass}}{\text{molar mass}}

For NH_{3},

\text{given mass}=3g

\text{molar mass}=14+3=17g

n_{NH_{3}}=\frac{3}{17}=0.176

For HCl,

\text{given mass}=5g

\text{molar mass}=1+35.5=36.5g

n_{HCl}=\frac{5}{36.5}=0.136

The reaction between NH_{3} and HCl is

NH_{3}+HCl→NH_{4}Cl

So,one mole of NH_{3} requires one mole of HCl

0.176 moles of NH_{3} requires 0.176 moles of HCl

But there are only 0.136 moles of HCl available.

HCl will be consumed first.

So,HCl is the limiting reagent.

7 0
3 years ago
Potassium and sodium chloride are similar in charge and they both have the same anion.  When comparing sodium chloride (36 g / 1
lesya [120]
Sodium Chloride has a higher solubility. 
7 0
3 years ago
H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).
timofeeve [1]

Answer:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

  • an equilibrium constant is, first of all, a fraction;
  • in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
  • in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
  • each concentration should be raised to the power of the coefficient in the balanced chemical equation;
  • only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

4 0
3 years ago
Number of moles in 37g of magnesium​
Ne4ueva [31]
Rounded its 1.522 mol
3 0
3 years ago
(8.6 1029) 7.4 X1029)
andrew11 [14]

Answer:

65563.914234

Explanation:

8.61029 x 7.4 x 1029

63.716146 x 1029

multiply

= 65563.914234

3 0
3 years ago
Read 2 more answers
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