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3 years ago

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Chemistry

2 answers:

Llana [10]3 years ago

8 0

Answer:

B. Is the correct answer :) i hope this helps!!

Explanation:

brainliest please?

marshall27 [118]3 years ago

7 0

The answer for this question is B

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A nonaqueous solution has a solvent that is not water. Which is an example of a nonaqueous solution?

Tom [10]

Answer:

Tincture o iodine.

Explanation:

If a solute is dissolved in a solution that is not water for example, alcohol, ether, carbon disulphide, Carbon tetrachloride and many other carbon based liquids, the resulting solution is classified as a non aqueous solution.

An example of such a solution is tincture of iodine made by dissolving in 1 liter alcohol.

The molarity of iodine is approximately 0.53M

The solution is largely used as a sore disinfectant.

5 0

3 years ago

Un ejemplo de levigacion

Nana76 [90]

La levigación es el proceso de moler una sustancia insoluble en un polvo fino, mientras está húmedo. El material se introduce en el molino junto con agua, en la cual la sustancia en polvo permanece suspendida, y fluye del molino como un líquido turbio o una pasta delgada, de acuerdo con la cantidad de agua empleada.

6 0

4 years ago

Aluminum chloride can be formed from its elements:

saul85 [17]

<u>Answer:</u> The $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical reaction for the formation reaction of $AlCl_3$ is:

$2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3 (s)$ $\Delta H^o_{formation}=?$

The intermediate balanced chemical reaction are:

(1) $HCl(g)\rightarrow HCl(aq.)$ $\Delta H_1=-74.8kJ$ ( × 6)

(2) $H_2(g)+Cl_2(g)\rightarrow 2HCl(g)$ $\Delta H_2=-185kJ$ ( × 3)

(3) $AlCl_3(aq.)\rightarrow AlCl_3(s)$ $\Delta H_3=+323kJ$ ( × 2)

(4) $2Al(s)+6HCl(aq.)\rightarrow 2AlCl_3(aq.)+3H_2(g)$ $\Delta H_4=-1049kJ$

The expression for enthalpy of formation of $AlCl_3$ is,

$\Delta H^o_{formation}=[6\times \Delta H_1]+[3\times \Delta H_2]+[2\times \Delta H_3]+[1\times \Delta H_4]$

Putting values in above equation, we get:

$\Delta H^o_{formation}=[(-74.8\times 6)+(-185\times 3)+(323\times 2)+(-1049\times 1)]=-1406.8kJ$

Hence, the $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

6 0

3 years ago

The bond enthalpy of the oxygen-oxygen bond in O2 is 498 kJ/mol. Based on the enthalpy of the reaction represented above, what i

kirill115 [55]

The given question is incomplete. The complete question is as follows.

The enthalpy of formation of ozone is 142.7 kJ / mol. The bond energy of $O_{2}$ is 498 kJ / mol. What is the average O=O bond energy of the bent ozone molecule O=O=O?