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klasskru [66]
3 years ago
12

Number three please how ever gets it first gets brainliest

Chemistry
2 answers:
Free_Kalibri [48]3 years ago
8 0
We can’t see the energy pyramid.
tankabanditka [31]3 years ago
7 0
Can’t answer that because we need to see the energy pyramid
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A solution of NaCl ( aq ) is added slowly to a solution of lead nitrate, Pb ( NO 3 ) 2 ( aq ) , until no further precipitation o
dezoksy [38]

Answer:

0.218 M of Pb(NO3)2

Explanation:

Equation of the reaction

Pb(NO3)2(aq) + 2NaCl(aq) --> PbCl2(s) + 2NaNO3(aq)

1 mole of Pb(NO3)2 reacts to precipitate 1 mole of PbCl2

Molar mass of PbCl2 = 207 + (35.5*2)

= 278 g/mol

Number of moles of PbCl2 precipitated = mass/molar mass

= 12.11/278

= 0.04356 mol

Since 0.04356 moles of PbCl2 was precipitated, therefore by stoichiometry; 0.04356 moles of Pb(NO3)2 reacted.

Molarity is defined as the number of moles of solute in 1 liter of solution.

Molarity = number of moles/volumes

= 0.04356/0.2

= 0.218 M

6 0
4 years ago
HELPPPPPP! PLEASE ASAPPPPPPPPPPPP!?
stiv31 [10]

answer:

millions of animals..

hope my ans helps

please give brainliest to my answer

be sure to follow me

stay safe

have a good day

3 0
3 years ago
Helppppppppppppppppppppppppp
Georgia [21]

Answer:

2 elements and one compund i think

Explanation:

4 0
3 years ago
Pleaseeeeeee hlepThe half-life of cobalt-60 is 5.26 years. After 10.52 years, 5 grams of a 20-gram sample will remain.
vladimir1956 [14]

The half-life of cobalt-60 is 5.26 years. After 10.52 years, 5 grams of a 20-gram sample will remain is TRUE

<u>Explanation:</u>

Mass of cobalt = 20 g  

Half-life = 5.26 years  

Mass remains after 10.52 years = 5 g  

This can be solved by using given below formula, m(t)=m_{o}\left(\frac{1}{2}\right)^{\frac{l}{5.26}}

m_{0} = initial mass  

t = number of years from when the mass was m_0  

m(t) = remaining mass after t years  

Number of half-lives = \frac{\text { Time elapsed }}{\text { Half -life }}

Number of half-lives = \frac{10.52 \text { years }}{5.26 \text { years }}

Number of half-lives = 2  

At time zero = 20 g  

At first half-life = \frac{20\ g}{2}  = 10 g  

At second half life = \frac{10\g}{2} = 5 g  

The given statement is true.

4 0
3 years ago
What is the mass of carbon monoxide (CO) gas if the gas occupies a volume of 4.1 L at 2.0 atm of pressure and -73oC?
Stels [109]

Answer:

1.7

Explanation:

4 0
2 years ago
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