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kogti [31]
3 years ago
13

Answer number 3 plzz

Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
7 0

Answer:

energy

Explanation:

it is required energy to remove an electron from an atom

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2. How much force, in g cm / s2 , is exerted by a golf ball described in problem 1 striking a tree while accelerating at 20 cm /
Lana71 [14]

Answer:

F = 1000 g cm/s²

Explanation:

Let the weight of 1 ball is 50 gram

Acceleration, a = 20 cm/s²

We need to find the force exerted by a golf ball. We know that,

F = ma

So,

F = 50 g × 20 cm/s²

F = 1000 g cm/s²

So, the required force is 1000 g cm/s².

5 0
3 years ago
25% While standing in line, a student notices that some students are really tall, some are approximately her height, and others
stiv31 [10]

Answer:

b

Explanation:

the answere is b

4 0
3 years ago
Write the formula for each of the following. (a) sodium carbonate (b) sodium bicarbonate (c) carbonic acid (d) hydrofluoric acid
user100 [1]

(A) Na2CO3

(B) NaHCO3

(C) H2CO3

(D) HF

(E) SO3

(F) CuSO4

(G) H2SO4

(H) H2S

- Remember to place the subscripts correctly. Hope I helped.

6 0
3 years ago
Read 2 more answers
A solution of the primary standard potassium hydrogen phthalate (KHP), KHC8H4O4 , was prepared by dissolving 0.4877 g of KHP in
Grace [21]

Answer:

The concentration of KOH is  0.06137 M

Explanation:

Step 1: Data given

Molar mass of KHP = 204.22 g/mol

Mass of KHP = 0.4877 grams

Volume of water = 50 mL

Volume of KOH solution = 38.91 mL

Step 2: The balanced equation

C8H5KO4 + KOH ⇒ C8H4K2O4+ H2O

Step 3: Calculate number of moles of KHP

Moles = Mass / molar mass

Moles KHP = 0.4877 grams / 204.22 g/mol

Moles KHP = 0.002388 moles

Step 4: Calculate moles of KOH

For 1 mol KHP we need 1 mol KOH to produce 1 mol C8H4K2O4 and 1 mol H2O

For 0.002388 moles KHP we need 0.002388 moles KOH

Step 5: Calculate the concentration of KOH

Concentration = moles / volume

Concentration of KOH = 0.002388 moles / 0.03891 L

Concentration of KOH = 0.06137 M

The concentration of KOH is  0.06137 M

4 0
3 years ago
Oran fills in the table below to organize information about the gas laws.
podryga [215]

Answer:2,4&5 A.

Explanation:

6 0
4 years ago
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