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3 years ago

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Chemistry

1 answer:

Lerok [7]3 years ago

5 0

Point c because it is being cycled into the denser magma closer to the core. while point b is closer to the surface (less dense)

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Convert the following into balanced equations:

enyata [817]

Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃

We must first convert from a word equation to a symbol equation:to a symbol equation:

Lead (II) Nitrate + Potassium Iodide → Lead (II) Iodide + Potassium Nitrate

The lead (II) ion is represented as Pb²⁺ , whilst the nitrate ion is NO⁻₃

To balance the charges, we require two nitrate ions per lead (II) ion, and so lead (II) nitrate is Pb(NO₃)₂

The potassium ion is K ⁺ and the iodide ion is I ⁻

The two charges balance in 1:1 ratio, giving a formula of KNO₃

The symbol equation is as follows:

Pb(NO₃)₂ + KI →PbI₂ + KNO ₃

The most obvious change we must make, when balancing this equation, is to increase the number of nitrate ions on the right hand side of the equation. We can to this by placing a coefficient of 2 before the potassium nitrate:

Pb(NO₃)₂ +KI →PbI₂ +2KNO₃

In doing this we have upset the balance of potassium ions on each side of the equation.

Again, we can fix this: we must simply place another coefficient of 2, this time before the potassium iodide:

Pb(NO₃)₂ +2KI → PbI₂ +2KNO ₃

Concluding :

Checking over the equations once more, you will notice that we initially had 1 iodide ion on the right hand side, but 2 on the left. However, we already dealt with this in balancing out potassium ions. Now, our equation is balanced.

And that's it! One last thing to add is that you may have noticed the irregularity in iodide ions rather than nitrate ions. In this case, you would arrived at the same answer simply by working backwards.

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3 0

2 years ago

For each of the following solutions, calculate [OH- ] from [H3O + ] or [H3O + ] from [OH- ]. Classify each solution as acidic, b

Yuri [45]

The case is acidic since calculated pH is below 7 that is 2.3

The hydroxide and hydrogen ion levels in a solution are the sources for calculating pOH and pH levels, respectively, and are the basis of whether a solution is acidic or basic

[H₃O+]=5.3×10⁻³M

To determine the hydroxide ion concentration, we use:

[OH−][H3O+]=1×10⁻¹⁴

We isolate the hydroxide ion concentration:

[OH−]=1×10−145.3×10⁻³M

Solving this, we obtain:

[OH−]=1.9×10−¹²M

We can determine whether the solution is acidic or basic by calculating the pH level:

pH=−log[H3O+]

We substitute in the hydronium ion concentration given:

pH=−Log(5.3×10−3)pH=2.3

Since the pH is below 7, the solution is acidic

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2 years ago

The pyruvate dehydrogenase complex catalyzes the oxidative decarboxylation of pyruvate to form acetyl‑CoA. E1 , E2 , and E3 are

Nana76 [90]

It’s B Thiamine puro pyrophosphate (TPP)

4 0

3 years ago

In which atmosphere layer does 80% of the gas in the atmosphere reside

Irina-Kira [14]

Answer:troposphere

Explanation:The troposphere is the layer that holds 80 percent of the total gas in the atmosphere.

4 0

3 years ago

The plant structure that helps transport water and nutrients from the roots to the leaves and other parts of the plant is

devlian [24]

The answer is Xylem. The plant structure that helps transport water and nutrients from the roots to the leaves and other parts of the plant is Xylem. In vascular plants, plants that have TUBELIKE STRUCTURES that carry water, nutrients, and other substances throughout the plant have xylem (<span>vascular tissue that carries water upward from the roots to every part of a plant) </span>and phloem (vascular tissue tubelike vessels that transport sugar made in photosynthesis from leaves to plant).

4 0

4 years ago

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