Answer:
79.7%
Explanation:
Percent yield of reaction is defined as the ratio between theoretical yield of a reaction and actual yield obtained.
In the problem, theoretical yield are 6 moles of KNO₃ and actual yield are 4.78 moles. Thus, percent yield is:
4.78 mol / 6 mol × 100 =<em> 79.7%</em>
