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irinina [24]
3 years ago
9

How many grams of NH3 can be produced from 4.89 mol of N2 and excess H2.

Chemistry
1 answer:
Svetllana [295]3 years ago
3 0

Answer:

166.56g of NH3 are produced

Explanation:

The reaction of N2 with H2 to produce NH3 is:

N2 + 3H2 → 2NH3

<em>Where 1 mole of N2 produce 2 moles of NH3</em>

<em />

4.89 moles of N2 with excess of H2 produce:

4.89 moles N2 * (2 moles NH3 / 1 mole N2) = 9.78 moles NH3

As molar mass of NH3 is 17.031g/mol, mass of NH3 produced is:

9.78 moles * (17.031g / mol) =

<h3>166.56g of NH3 are produced</h3>
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