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3 years ago

3. Given the following equation:

Chemistry

1 answer:

miskamm [114]3 years ago

4 0

Answer:

4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

Explanation:

The balanced equation is

2 K+ Cl2 --->2 KCI

Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K

Mass of one atom/mole of potassium is 39.098 grams

Number of moles is 2.5 grams = $\frac{2.5}{39.098} = 0.064$

So, 2 moles of K produces 2 moles of KCL

0.064 moles of K will produces 0.064 moles of KCl

Mass of one molecule of KCl is 74.5513 g/mol

Mass of 0.064 moles of KCl is 4.767 grams

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almond37 [142]

D. How the pull of gravity has changed.

4 0

3 years ago

An element has three different isotopes. One has a mass of 35.00 amu; another has a mass of 36.00 amu; and another has a mass of

yulyashka [42]

Answer:

so 35+38+36÷3= 109÷3 =36.33 AMU

8 0

3 years ago

HELP ME OUT PLEASE!!!!!!!!

34kurt

Answer:

49.979

Explanation:

4 0

2 years ago

atch the following aqueous solutions with the appropriate letter from the column on the right. fill in the blank 1 A 1. 0.20 m N

Firdavs [7]

Answer:

Highest boiling point - 0.43 m Urea

Second highest boiling point - 0.20 m NiSO4

Third highest boiling point - 0.19 m NH4I

Lowest boiling point - 0.17 m NH4NO3

Explanation:

We know that;

ΔT = kb m i

Where;

ΔT = boiling point elevation

kb = boiling point constant

m = molality of the solution

i = Van't Hoff factor

For NiSO4 , NH4I and NH4NO3 , the Van't Hoff factor, i = 2

But for Urea, the Van't Hoff factor, i = 1

We also have to consider both the values of the molality and Van't Hoff factor , knowing that a higher molality and a higher Van't Hoff factor leads to a higher ΔT and consequently a higher boiling point.

This facts above account for the arrangement of substances shown in the answer.

6 0

3 years ago

choose the reaction that illustrates delta H *f for Ca(NO3)2.(A) Ca (s) + N2 (g) + 3O2 ---> Ca(NO3)2 (s)(B) Ca2 (aq) + 2 NO3-

kompoz [17]

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Standard enthalpy of formation is the change in enthalpy of one mole of a substance present at the standard state that is 1 atm of pressure and 298 K of temperature. The substance is formed from its pure elements under the same conditions.

We are given a chemical compound having chemical formula $Ca(NO_3)_2$

This compound is formed by the combination of calcium, nitrogen and oxygen elements.

The chemical equation for the formation of $Ca(NO_3)_2$ from the components in their standard states follows:

$Ca+N_2+3O_2\rightarrow Ca(NO_3)_3$

Hence, the correct answer is Option A.

3 0

3 years ago