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lara [203]
3 years ago
11

3. Given the following equation:

Chemistry
1 answer:
miskamm [114]3 years ago
4 0

Answer:

4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

Explanation:

The balanced equation is

2 K+ Cl2 --->2 KCI

Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K

Mass of one atom/mole of potassium is 39.098 grams

Number of moles is 2.5 grams = \frac{2.5}{39.098} = 0.064

So, 2 moles of K produces 2 moles of KCL

0.064 moles of K will produces 0.064 moles of KCl

Mass of one molecule of KCl is 74.5513 g/mol

Mass of 0.064 moles of KCl is 4.767 grams

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Oksi-84 [34.3K]
The sulphate ion has a charge of 2-, and potassium has a charge of 1+. To fully neutralise the charge on a sulphate ion, you need two potassium ions. 

However, strontium has a charge of 2+. To neutralise the sulphate ion's 2- charge, one strontium ion is enough, so only one bonds to the sulphate.

Hope I helped! xx
7 0
3 years ago
What is the identity of the resulting atom
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4 years ago
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6 0
3 years ago
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Maru [420]

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