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Dima020 [189]
3 years ago
7

A t-test is suitable for

Chemistry
1 answer:
blagie [28]3 years ago
7 0

Answer:

Explanation:

A t-test is a type of inferential statistic used to determine if there is a significant difference between the means of two groups, which may be related in certain features. The t-test is one of many tests used for the purpose of hypothesis testing in statistics. Calculating a t-test requires three key data values.

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For a grating, how many lines per millimeter would be required for the first order diffraction line for λ = 400 nm to be observe
MA_775_DIABLO [31]

Answer:

For a grating, how many lines per millimeter would be required for the first order diffraction line for λ = 400 nm to be observed at a reflection angle of 5^{o} when the angle of incidence is  45^{o}?

<em>The number of lines per mm is 1985 lines </em>

Explanation:

A diffraction grating is used to separate a light source with multiple wavelengths into single wavelengths of different colors using the principle of diffraction.

Calculating for the spacing between the reflected surfaces

The spacing between the reflecting surfaces can be obtained using the relationship with the wavelength as shown below;

nA = d (sin i + sin r) ....................................1

where n is the order of diffraction = 1;

A is the wavelength = 400 nm

i is the angle of incidence = 45^{o}

r is the angle of refraction =  5^{o}

making d the subject formula from equation 1 we have;

d = \frac{nA}{sin i + sin r}...........................2

Now we substitute the given parameters into equation 2;

d = \frac{1(400 nm)}{(sin 45^{o}  ) + (sin 5^{o} )}

d = \frac{400 nm}{0.707 +0.087}

d = 503.7 nm

The spacing between reflecting surfaces is 503.7 nm

Calculating for the number of lines per millimeter

To calculate the number of spacing per millimeter we convert nanometer to millimeters, 1 mm =10^{6} and 1 line = 503.7 nm;

1 mm *\frac{1 line}{503.7 nm} *\frac{10^{6} }{mm}

= 1985 lines

Therefore the number of lines per millimeter would be 1985 lines

6 0
3 years ago
How many valence electrons does a helium atom have? what is the formula of the ion formed when potassium achieves noble-gas elec
OlgaM077 [116]

> How many valence electrons does a helium atom have?

The electron configuration of Helium is simply 1s2. We see that its outermost shell is the s shell and it contains 2 electrons, therefore the number of valence electrons is also 2.

 

> What is the formula of the ion formed when potassium achieves noble-gas electron configuration?

Potassium has a electron configuration of [Ar] 4s1. To have an electron configuration of only [Ar] which is a noble gas, the one electron from 4s1 should be removed, hence:

<span>K+</span>

3 0
3 years ago
The pOH of a solution is 10.75. What is the concentration of OH– ions in the solution?
Lubov Fominskaja [6]
The correct answer is 1.778 x 10^-11M. Hope this helps.
4 0
3 years ago
A balloon has a maximum capacity of 1700 m3. On a cool morning (temperature = 10°c, some hot-air balloonists start filling their
bulgar [2K]

V1/T1 = V2 / T2

V1 = 3/4(1700) = 1275

T1 = 10 + 273.15 = 283.15

V2 = 1700

T2 = V2T1

T2 = (1700) (283.15) / 1275

T2 = 377.53 K

7 0
3 years ago
How many atoms are centered on the (100) plane for the fcc crystal structure?
Setler [38]

Here, we have to get the number of atoms present in the 100 plane of the FCC crystal lattice.

There will be 2 atoms in 100 plane of FCC crystal lattice.

In the face centered crystal (FCC) lattice there are atoms at each corner of the cube and each are shared by 4 another atoms. And an atom is present at the face of the crystal.

For the 100 plane of the Miller indices the intercepts are a, ∞, ∞ or 2a, ∞, ∞.

Thus, for the 4 atoms of the corner at the cube shared by 4 other atoms will contribute, 4 × \frac{1}{4} = 1 and the un-shared atoms at the face will contribute another 1, which make the total atom 1 + 1 = 2.

5 0
3 years ago
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