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1 year ago

Name this compound. Please help

Chemistry

1 answer:

fgiga [73]1 year ago

4 0

Answer:

mitosis

Explanation:

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3 years ago

What is the percent-by-mass concentration of acetic acid (CH3COOH) in a vinegar solution that contains 51.80 g acetic acid in a

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Answer : The percent-by-mass concentration of acetic acid is, 5.15 %

Explanation : Given,

Mass of acetic acid = 51.80 g

Density of solution = 1.005 g/ml

Volume of solution = 1.000 L = 1000 ml (1 L = 1000 ml)

First we have to calculate the mass of solution.

$\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}$

$\text{Mass of solution}=1.005g/ml\times 1000ml=1005g$

Now we have to calculate the percent-by-mass concentration of acetic acid.

$\% \text{ by mass of acetic acid}=\frac{\text{Mass of acetic acid}}{\text{Mass of solution}}\times 100$

Now put all the given values in this formula, we get:

$\% \text{ by mass of acetic acid}=\frac{51.80g}{1005g}\times 100=5.15\%$

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2 years ago

A chemical reaction occurring in a cylinder equipped with a moveable piston produces 0.601 mol of a gaseous product. If the cyli

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Answer:

4.33 L

Explanation:

Assuming ideal behaviour and that all 0.300 moles of gas reacted, we can solve this problem using Avogadro's law, which states that at constant temperature and pressure:

V₁n₂ = V₂n₁

Where in this case:

V₁ = 2.16 L

n₂ = 0.601 mol

V₂ = ?

n₁ = 0.300 mol

We <u>input the given data</u>:

2.16 L * 0.601 mol = V₂ * 0.300 mol

And <u>solve for V₂</u>:

V₂ = 4.33 L

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2 years ago

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Hope this helps :).

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