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Luba_88 [7]
2 years ago
11

Name this compound. Please help

Chemistry
1 answer:
fgiga [73]2 years ago
4 0

Answer:

mitosis

Explanation:

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The student is now told that the four solids, in no particular order, are calcium bromide (CaBr2), sugar (C6H12O6), benzoic acid
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<h2>Answer : The order of conductivity from most conductive to least is this - </h2><h2>Calcium bromide (CaBr_{2}), Potsassium bromide (KBr), Benzoic acid C_{6}H_{5}COOH and last is sugar.</h2><h3>Explanation : </h3>

When dissolved in water  (CaBr_{2}) produces three ions namely; Ca^{+2} and 2Br^{-} which acts as best conductor amongst the given choices.

Next is potassium bromide when dissolved in water generates only two ions which are K^{+} and Br^{-} and acts as an conductor.

Benzoic acid C_{6}H_{5}COOH, is a weak acid and is slightly ionized so it acts as an weak conductor.

Sugar is a non ionized compound so it is anon conductor.

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3 years ago
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In Universe L , recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, qua
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Answer:

See explanation

Explanation:

The third and fourth elements in the first transition series are vanadium and chromium. They contain 23 and 24 electrons respectively.

In universe L, the electron configuration of vanadium is;

[X]  3d3 4s2

In universe L, the electron configuration of chromium is;

[X] 3d4 4s2

The electron configuration of chromium has to change since there are four instead of five d orbitals in universe L.

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3 years ago
In order for an organism to survive, what must it do?
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Cerium (IV) ions are strong oxidizing agents in acid ic solution, oxidizing arsenio us acid to arsen ic acid accor ding to the f
kirill [66]

Answer:

0.2042 M is the original concentration of Ce^{4+} (aq) in the titrating solution.

Explanation:

Mass of As_2O_3 = 0.217 g

Moles of As_2O_3=\frac{0.217 g}{198 g/mol}=0.001096 mol

1 mole of As_2O_3 have 2 mole of As  and 1 mole of H_3AsO_3 have 1 mole of As.

So, from 1 mole of As_2O_3 we will have 2 moles of H_3AsO_3

Then from 0.001096 mol of As_2O_3 :

2\times 0.001096 mol=0.002192 mol of H_3AsO_3

2Ce^{4+}(aq)+H_3AsO_3(aq)+3H_2O(l)\rightarrow 2Ce^{3+}(aq)+H_3AsO_4(aq)+2H^+(aq)

According to reaction, 1 mole of H_3AsO_3 reacts with 2 mole of cerium (IV) ions,then 0.002192 mol of

\frac{2}{1}\times 0.002192 mol=0.004384 mol of cerium (IV) ions.

Volume of the  acidic cerium{IV) sulfate = 21.47 ml =0.02147 L

1 mL = 0.001 L

concentration = \frac{Moles}{Volume(L)}

[Ce^{4+}]=\frac{0.004384 mol}{0.02147 L}=0.2042 M

0.2042 M is the original concentration of Ce^{4+} (aq) in the titrating solution.

8 0
3 years ago
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