How many electrons does H have with a -1 charge
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Hoffman Product is always a less substituted alkene. In given scenario Structure A (Given Below) was taken as a starting chiral Amine. For the sake of elimination the amine was taken tertiary so that on methylation it becomes a good leaving group. This chiral amina (A) when treated with Methyl Iodide gives a quarternary amine which on treatment with Silver oxide yields less substituted Alkene (B) as shown Below.
Alkene B on Ozonolysis give two aldehydes i.e. Formaldehyde and Butyraldehyde.
Alkene B on Ozonolysis give two aldehydes i.e. Formaldehyde and Butyraldehyde.