Answer:
If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.
Explanation:
Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure
V ∝ 1/P or V₁·P₁ = V₂·P₂
Where:
V₁ = Initial volume
V₂ = Final volume = V₁/2
P₁ = Initial pressure = 832 torr
P₂ = Final pressure = Required
From V₁·P₁ = V₂·P₂ we have,
P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)
P₂ = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr
Answer:
Explanation:
Hello there!
In this case, since this concentration of hydronium ions is given, we infer we may calculate that of the hydroxide ions, pH and pOH because no question was specifically given. That is why we proceed as follows:
- pH: Here, we use this concentration to calculate the pH according to the negative logarithm:

Which means that the solution is acidic as the pH is less than 7.
- pOH: since the pH added to the pOH is 14, we can calculate the latter as follows:

- Hydroxide concentration: Given the pOH, we apply the antilogarithm to calculate such concentration as shown below:
![[OH^-]=10^{-pOH}=10^{12.56}=2.75x10^{-13}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-pOH%7D%3D10%5E%7B12.56%7D%3D2.75x10%5E%7B-13%7DM)
Keep in mind, this is an arbitrary solution because no question was provided.
Regards!