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Blizzard [7]
4 years ago
12

Polyethylene is a synthetic polymer or plastic with many uses. 1.36 g of a polyethylene sample was dissolved in enough benzene t

o make 100. mL of solution, and the osmotic pressure was found to be 1.86 torr at 25oC. What is the approximate molar mass of the polyethylene?
Chemistry
1 answer:
trapecia [35]4 years ago
3 0

Answer:

Molar mass = 1.111 × 10⁻⁵ g/mol

Explanation:

Given data:

Mass of polyethylene = 1.36 g

Volume = 100 mL   (0.1 L )

Pressure = 1.86 torr (1.86/760 = 0.003 atm)

Temperature = 25 °C = 25 °C + 273.15 = 298.15 K

Molar mass of polyethylene = ?

Solution :

PV =nRT

n = PV/RT

n = 0.003 atm × 0.1 L / 0.0821 atm. L . mol⁻¹ .k⁻¹  × 298.15 k

n = 0.0003 atm. L / 24.5 atm. L . mol⁻¹

n = 1.2245 × 10⁻⁵ mol

Molar mass = mass / number of moles

Molar mass = 1.36g / 1.2245 × 10⁻⁵ mol

Molar mass = 1.111 × 10⁻⁵ g/mol

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3 years ago
Suppose you carry out a titration involving 3.00 molar HCl and an unknown concentration of KOH. To bring the reaction to its end
snow_tiger [21]

Answer: The concentration of the KOH solution is 1.01 M

Explanation:

According to neutralization law:

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where,

n_1 = basicity of HCl = 1

n_2 = acidity of KOH = 1

M_1 = concentration of HCl = 3.00 M

M_2 = concentration of KOH = ?

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V_2 = volume of KOH = 105.0 ml

Putting the values we get:

1\times 3.00\times 35.3=1\times M_2\times 105.0

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3 0
4 years ago
Given a balanced chemical equation between H2SO4(aq) and KOH(aq) H2SO4(aq) + 2 KOH(aq) → K2SO4(aq) + 2 H2O(l) What volume (in mL
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Answer:

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From the question:

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Cross multiply to express in linear form

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Va = (0.35 x 120) /(2 x 0.43)

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