Which question the top part, middle or the 7 covalents?
- The force acting on the box is 27N
- The acceleration of the car is 0.30 m/s²
- The object's mass is 2 kg
<h3>Newtons 2nd law </h3>
From Newton's second law,
F = ma
Where F is the force
m is the mass
and a is the acceleration
Q.1
Here, we are to determine the force acting on the box
m = 3 kg
a = 9 m/s²
Using the formula,
F = ma
F = 3 × 9
F = 27N
Hence, the force acting on the box is 27N
Q.2
Here, we are to determine the acceleration of the car
m = 780 kg
F = 235 N
Using the same formula,
F = ma
235 = 780 × a
a = 235 / 780
a = 0.30 m/s²
Hence, the acceleration of the car is 0.30 m/s²
Q.3
Here, we are to determine the object's mass
a = 5 m/s²
F = 10 N
Using the same formula,
F = ma
10 = m × 5
m = 10 / 5
m = 2 kg
Hence, the object's mass is 2 kg
Learn more on Newton's 2nd law here: brainly.com/question/13839211
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D is the answer, Public op about a scientific issue
Answer:
992.302 K
Explanation:
V(rms) = 750 m/s
V(rms) = √(3RT / M)
V = velocity of the gas
R = ideal gas constant = 8.314 J/mol.K
T = temperature of the gas
M = molar mass of the gas
Molar mass of CO₂ = [12 + (16*2)] = 12+32 = 44g/mol
Molar mass = 0.044kg/mol
From
½ M*V² = 3 / 2 RT
MV² = 3RT
K = constant
V² = 3RT / M
V = √(3RT / M)
So, from V = √(3RT / M)
V² = 3RT / M
V² * M = 3RT
T = (V² * M) / 3R
T = (750² * 0.044) / 3 * 8.314
T = 24750000 / 24.942
T = 992.302K
The temperature of the gas is 992.302K
Note : molar mass of the gas was converted from g/mol to kg/mol so the value can change depending on whichever one you use.