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Sedaia [141]
3 years ago
10

To what category of elements does an element belong if it is a poor conductor of electricity? (1 point)

Chemistry
1 answer:
qwelly [4]3 years ago
4 0
Nonmetals is the answer

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B,C

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Student A is pulling 57 newtons and student B is pushing at 96 newtons. What is the net force?
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153 N left

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Explanation:

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One scientific investigation may result in
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a new discover a new theory

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The pressure of a 1-L nitrogen gas sample at 25 ⁰C is 0.30 atm. The pressure of a 1-L oxygen gas sample at the same temperature
ki77a [65]

Answer:

Nitrogen = 0.3 atm

Oxygen = 0.25 atm

Argon  = 0.45 atm

Explanation:

According to Dalton's law of partial pressure, the total pressure in the container is equal to sum of the partial pressures of the individual gases.

Given;

Total pressure of the gases, P_total = 1 atm

Pressure of nitrogen, P_nitrogen = 0.3 atm

Pressure of oxygen, P_oxygen = 0.25 atm

Pressure of argon, P_argon = ?

P_{total} = P_{nitrogen} + P_{oxygen} + P_{argon}\\\\1 \ atm= 0.3 \ atm + 0.25 \ atm + P_{argon}\\\\1 \ atm= 0.55 \ atm +  P_{argon}\\\\ P_{argon} = 1 \ atm - 0.55 \ atm\\\\ P_{argon} = 0.45 \ atm

Therefore, the contribution of each gas to the total pressure of the gas mixture is;

Nitrogen = 0.3 atm

Oxygen = 0.25 atm

Argon  = 0.45 atm

8 0
3 years ago
For the reaction, 2cr2+ + cl2(g) ---> 2cr3+ + 2cl- e cell (standard conditions) = 1.78v calculate ecell (standard conditions)
PolarNik [594]

Answer:

-1.78 V

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There are several rules required to calculate the cell potential:

  • given standard cell potential, we may reverse the equation: the products of a given reaction become our reactants, while reactants become our products in the reversed equation. For a reversed equation, we change the sign of the cell potential to the opposite sign;
  • if we multiply the whole equation by some number, this doesn't influence the cell potential value. It only produces a different expression in the equilibrium constant.

That said, notice that the initial reaction with respect to the final reaction is:

  • reversed: chromium(III) cation and chloride anion become our reactants as opposed to the products in the initial reaction, so we change the sign of the cell potential to a negative value of -1.78 V;
  • each coefficient is multiplied by a fraction of \frac{1}{2}. It doesn't influence the value of the cell potential.

Thus, we have a cell of E = -1.78 V.

3 0
3 years ago
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