The pH of the solution is mathematically given as
PH=7.21
<h3>What would be the pH of the solution?</h3>Question Parameters:
sodium hydrogen sulfite (NaHSO3) to 50 mL of water.
Generally, the equation for the Chemical Reaction for the acid dissociation is mathematically given as
HSO3- + H2O ---> H3O+ + SO3^2-
Therefore
A-=HA
pH=pKa
Since pKa NaHSO3=7.21
Hence, PH=7.21
For more information on Chemical Reaction
Answer:
9.28
Explanation:
pOH refers to a measure of hydroxide ions concentration. pOH tells about the alkalinity of a solution. If pOH is less than 7 then aqueous solutions are alkaline, acidic if pOH is greater than 7 and neutral if pOH is equal to 7.
Concentration of the hydroxide ions = 1.9 x 10-5 M
pH =
pOH = 14 - pH
=14 - 4.72 = 9.28
<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
To calculate the amount of heat absorbed or released, we use the following equation:
.....(1)
where, q = amount of heat absorbed or released.
m = mass of the substance
c = heat capacity of water = 4.186 J/g ° C
= Change in temperature
We are given:
Putting values in equation 1, we get:
q = 5023.2 J
We are given:
Putting values in equation 1, we get:
q = 1674.4 J
Heat gained by Trial 1 than trial 2 =
Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.
Thus, the correct answer is Option b.