) If you prepared a solution by adding equal numbers of moles of sodium sulfite (Na2SO3) and sodium hydrogen sulfite (NaHSO3) to

Question

1 year ago

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50 mL of water, what would be the pH of the solution

1 answer:

sashaice [31] · Answer 1 · 2023-06-29T00:30:09+03:00

The pH of the solution is mathematically given as

PH=7.21

<h3>What would be the pH of the solution?</h3>

Question Parameters:

sodium hydrogen sulfite (NaHSO3) to 50 mL of water.

Generally, the equation for the Chemical Reaction for the acid dissociation is mathematically given as

HSO3- + H2O ---> H3O+ + SO3^2-

Therefore

$pH=Pka+log\frac{A-}{Ha}$

A-=HA

pH=pKa

Since pKa NaHSO3=7.21

Hence, PH=7.21

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