Answer:
Step-by-step explanation:
sin²β + sin²β×tan²β = tan²β
sin²β( 1 + tan²β ) = tan²β
~~~~~~~~~~~~~~~~
<u><em>sin²β + cos²β = 1 </em></u>
<u><em /></u>
+ 
= 
⇒ tan²β + 1 = sec²β ⇔ 1 + tan²β = sec²β
~~~~~~~~~~~~~~
1 + tan²β = 
L.H. = sin²β ( ) = tan²β
R.H. = tan²β
Answer:
The intermediate step are;
1) Separate the constants from the terms in x² and x
2) Divide the equation by the coefficient of x²
3) Add the constants that makes the expression in x² and x a perfect square and factorize the expression
Step-by-step explanation:
The function given in the question is 6·x² + 48·x + 207 = 15
The intermediate steps in the to express the given function in the form (x + a)² = b are found as follows;
6·x² + 48·x + 207 = 15
We get
1) Subtract 207 from both sides gives 6·x² + 48·x = 15 - 207 = -192
6·x² + 48·x = -192
2) Dividing by 6 x² + 8·x = -32
3) Add the constant that completes the square to both sides
x² + 8·x + 16 = -32 +16 = -16
x² + 8·x + 16 = -16
4) Factorize (x + 4)² = -16
5) Compare (x + 4)² = -16 which is in the form (x + a)² = b
Answer:
8 square units
Step-by-step explanation:
x + 1 = 0
x = -1
x + 8 = 0
x = -8
Area = (-1) * (-8) = 8 square units
Just use pemdas
(Parenthesis, exponents, multiplication, division, addition, subtraction)
Answer:
8
Step-by-step explanation:
plz brainliestt
