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3 years ago

Please helppppppppppppppppppppp!!!!!!!!!!!!!!!

Mathematics

1 answer:

zavuch27 [327]3 years ago

8 0

Answer:

Step-by-step explanation:

the constant rate of change is the number before x in an equation (in ours its -2)

on a table just find where there are two x values that go up by one then see how much the y value goes up (in our case its 4)

hope this helps <3

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Show all your work please!

Tatiana [17]

Answer:

-3 and 5

Step-by-step explanation:

f(n) = n² - 2n - 15

numbers whose product is -15 and sums up to -2 = -5 and 3

= n²- 5n+3n - 15

= n(n - 5) +3 (n - 5)

f(n) = (n + 3)( n - 5)

n + 3 = 0 n - 5 = 0

n = -3 n = 5

Roots = -3 and 5

6 0

3 years ago

Anyone help please I need it

andreev551 [17]

Answer:

$-10+i\sqrt{2}$

Step-by-step explanation:

One is given the following expression:

$\sqrt{4}-\sqrt{-98}-\sqrt{144}+\sqrt{-128}$

In order to simplify and solve this problem, one must keep the following points in mind: the square root function ( $\sqrt{}$ ) is a way of requesting one to find what number times itself equals the number underneath the radical sign. One must also remember the function of taking the square root of a negative number. Remember the following property: ( $\sqrt{-1}=i$ ). Simplify the given equation. Factor each of the terms and rewrite the equation. Use the square root property to simplify the radicals and perform operations between them.

$\sqrt{4}-\sqrt{-98}-\sqrt{144}+\sqrt{-128}$

$\sqrt{2*2}-\sqrt{-1*2*7*7}-\sqrt{12*12}+\sqrt{-1*2*8*8}$

Take factors from out of under the radical:

$\sqrt{2*2}-\sqrt{-1*2*7*7}-\sqrt{12*12}+\sqrt{-1*2*8*8}$

$2-7i\sqrt{2}-12+8i\sqrt{2}$

Simplify,

$-10+i\sqrt{2}$

8 0

3 years ago

If √x / 6 = √x-1 / 3. What is x?

Pavlova-9 [17]

Option B is the answer
Hope this helps you..!!

3 0

4 years ago

The quotient of a and six less than a is identical to four more than the product of a and b.

ycow [4]

Answer:

a/(a-6) = ab + 4.

Step-by-step explanation:

3 0

3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

4 years ago