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Morgarella [4.7K]
3 years ago
5

Simply 1/2 × 1/8 ÷ 1

ormula1" title="simplify 1\2 \times 1\8 \div 1\2" alt="simplify 1\2 \times 1\8 \div 1\2" align="absmiddle" class="latex-formula">

​
Mathematics
2 answers:
Ivan3 years ago
7 0
The answer is = 1/16
djverab [1.8K]3 years ago
3 0

Answer:

1/8

Step-by-step explanation:

1/2×1/8÷1/2

=1/2×1/8×2

=2/2×1/8

=1×1/8=1/8

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Solve (2x + 3) - (9x - 3)
Diano4ka-milaya [45]

Answer:

-7x + 6

Step-by-step explanation:

3 0
3 years ago
Find the area and perimeter <br> please help me :)
Katarina [22]

Answer:

Perimeter: 44

Area: 96

Step-by-step explanation:

Perimeter - Just add all the sides together, 4 + 10 + 12 +7 + 8 + 3.

(The 8 and the 3 are apart of the sides that are not labeled. Since 12 - 4 = 8, and 10 - 7 = 3, That's where these numbers come from.)

Area - 4 * 10 = 40,

 +        8 * 7 =  56,

--------------------------------

                   = 96

I hope this helps :)

8 0
2 years ago
Read 2 more answers
A projectile fired at 5 m/s from a gun. If the horizontal component of the initial velocity is equal to 4 m/s. What is the value
svlad2 [7]

Answer:

the  \: value \:  of  \: the \:  vertical  \: component \to : \\  (v_v) = 3m {s}^{ - 1}  \\

Step-by-step explanation:

let \: the \: velocity \: be \to \: v \\let \: the \: horizontal \: component \: be \to \: v_h \\ let \: the \: vertical \: component \: be \to \: v_v \\ applying \: the \: pythagorean \: rule \: of \: vectors \to :  \\  {v}^{2}  =  {v_v}^{2}  +  {v_h}^{2}  \\  {v_v}^{2}  =  {v}^{2}  - {v_h}^{2}  \\ {v_v}^{2} = {5}^{2}  - {4}^{2}  \\ v_v =  \sqrt{(25 - 16)}  \\ v_v =  \sqrt{9}  \\ \boxed{ v_v = 3 {ms}^{ - 1} }

5 0
3 years ago
What is the area of the piece of red paper after the hole for
MakcuM [25]

Answer:

     \large\boxed{\large\boxed{47unit^2}}

Explanation:

The complete question is:

<em>A hole the size of a photograph is cut from a red piece of paper to use in a picture frame.</em>

<em />

<em>On a coordinate plane, 2 squares are shown. The photograph has points (-3, -2), (- 2, 2), (2, 1), and (1, -3). The red paper has points (- 4, 4), (4, 4), (4, -4), and (-4, -4).</em>

<em />

<em>What is the area of the piece of red paper after the hole for the photograph has been cut?</em>

<em />

<h2><em>Solution</em></h2>

<em />

The area of the piece of redpaper after the hole has been cut is equal to the area of the big square less the area of the small rectangle.

<u>1. Area of the big rectangle</u>

Vertices:

  • <em>(- 4, 4) </em>
  • <em>(4, 4)</em>
  • <em>(4, -4)</em>
  • <em>(-4, -4)</em>

<em />

The side length is the distance between two consecutive vertices:

The two points (-4,4) and (4,4) has the same y-coordinate, thus the length is just the absolute value of the difference of the x-coordinates:

  • 4-(-4)=4+4=8

The area of this square is    (8unit)^2=64unit^2

<u>2. Area of the small square</u>

Vertices:

  • <em>(-3, -2)</em>
  • <em>(- 2, 2) </em>
  • <em>(2, 1)</em>
  • <em>(1, -3)</em>

<em />

To find the side length use the distance formula for two consecutive points, for instance (2,1) and (-2,2):

      d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\ \\d=\sqrt{(2-(-2))^2+(2-1)^2}=\sqrt{4^2+1^2}=\sqrt{17}

The area is:

          (\sqrt{17}unit)^2}=17unit^2

<u>3. Area of the piece of red paper after the holw for the photograph has been cut:</u>

<u />

Find the difference:

<u />

         64unit^2-17unit^2=47unit^2

<em />

7 0
3 years ago
Read 2 more answers
How can I solve the following system of equations: -4x + y= 6, -5x -y =21. I know I can cancel out but I don't know where or whe
matrenka [14]
-4x + y = 6
-5x - y = 21

add both of them
-9x = 27
x = -3

(-4*-3) + y = 6
-12 + y = 6
y = 18
7 0
3 years ago
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