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REY [17]
3 years ago
7

A 1,000 kg truck initially had a velocity of 9 m/s. A force acts on it for a duration of time. After that force, the truck now h

as a velocity of 17 m/s. What is the impulse that the truck experienced?
Physics
1 answer:
OleMash [197]3 years ago
7 0

Answer:

8000Ns

Explanation:

Given parameters:

Mass of the truck  = 1000kg

Initial velocity  = 9m/s

Final velocity  = 17m/s

Unknown:

Impulse  = ?

Solution:

The impulse experienced by the truck is the the change in momentum of the body.

  Impulse  = Ft

        Momentum  = m(v  - u)

        Ft  = m( v - u )

 F is the force

 t is the time

 m is the mass

  v is the final velocity

 u is the initial velocity

     Impulse  = 1000(17 - 9) = 8000Ns

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Answer:

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<u><em>The resultant vector</em></u> is the vector sum of two or more vectors

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Lets solve the problem

A right triangle with the base labeled 40 meters and the height labeled

30 meters

The hypotenuse is a dotted arrow labeled R

→ The base and the height of the right triangle are perpendicular

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Assume that x represents the base of the triangle and y represents the

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By using the rule above

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→ R=\sqrt{x^{2}+y^{2}}

→ R=\sqrt{(40)^{2}+(30)^{2}}

→ R=\sqrt{1600+900}

→ R=\sqrt{2500}=50

<em>The magnitude of the resultant vector R is 50 meters</em>

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