If you can observe, we are only given one parameter here which is the time. If you want to compute for the distance, you have to know the speed. The hint here is the 'radio transmissions'. All the information gathered by the probe from the space, is sent back to the Earth by electromagnetic waves. Hence, we must know the speed of electromagnetic waves. Since they are as fast as light, their speed is equal to 300 million meters per second. Then, we can finally determine the distance.
d = speed*time
d = (300×10⁶ m/s)(2.53 hours)
Since 1 hour = 3,600 seconds,
d = (300×10⁶ m/s)(2.53 hours)(3,600 seconds/1 hour)
d = 2.73×10⁻¹² m
That is true. its more than twice as heavier
distance to the star Betelgeuse: 640 ly
As we know that
also we know that
So the distance of Betelgeuse = 640 ly
distance to the star VY Canis Majoris: 
distance to the galaxy Large Magellanic Cloud: 49976 pc
now we have
distance to Neptune at the farthest: 4.7 billion km
now the order of distance from least to greatest is as following
1. distance to Neptune at the farthest
2. distance of Betelgeuse
3. distance to the star VY Canis Majoris
4. distance to the galaxy Large Magellanic Cloud
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
