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3 years ago

This particle would have to have at least how many protons in order to have a positive charge?

Physics

1 answer:

jasenka [17]3 years ago

6 0

Answer: You don't do work.

Explanation: If you don't do the work you don't have to ask this question. With work comes labor. With labor comes change. With change comes resistance and people do not like change. IT causes anger, so if you stop doing work and stick to the important supply like food, water, and shelter you don't have to go through the trouble of this and we can live in a peaceful environment for this world to be better than it is. People do to much, it's a natural fact but you can change the entire picture. If you read all of this thank you for accepting the fact of life.

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A spring stretches by 0.014 m when a 3.7-kg object is suspended from its end. How much mass should be attached to this spring so

lidiya [134]

Explanation:

Below is an attachment containing the solution.

6 0

3 years ago

Consider projectile thrown horizontally at 50 m/s from height of 19.6 meters. The projectile will take ______________ time to hi

aleksley [76]

Answer:

C)The Same

Explanation:

Kinematics equation:

$y=v_{oy}*t+1/2*g*t^2$

for both cases the initial velocity in the axis Y is the same, equal a zero.

So the relation between the height ant temps is the same for both cases (the horizontal velocity does not play a role)

C)The Same

3 0

3 years ago

The thermal energy of what system does change

Inessa05 [86]

Answer:

there is the increase the temperature of cold body and decrease the temperature of hot body

4 0

2 years ago

A gray kangaroo can bound across level ground with each jump carrying it 9.1 m from the takeoff point. Typically the kangaroo le

Alona [7]

Answer:

u = 10.63 m/s

h = 1.10 m

Explanation:

For Take-off speed ..

by using the standard range equation we have

$R = u² sin2θ/g$

R = 9.1 m

θ = 26º,

Initial velocity = u

solving for u

$u² = \frac{Rg}{sin2\theta}$

$u^2 = \frac{9.1 x 9.80}{sin26}$

$u^2 = 113.17$

u = 10.63 m/s

for Max height

using the standard h(max) equation ..

$v^2 = (v_osin\theta)^2 -2gh$

$h =\frac{(v_o^2sin\theta)^2}{2g}$

$h = \frac{(113.17)(sin26)^2}{(2 x 9.80)}}$

h = 1.10 m

7 0

3 years ago

Convert the speed of light 3.0x10^8 m/s to km/day

Aleksandr [31]

Answer: $2.592 \times 10^{8}km/day$

$1 m = 0.001 km\\ 1 s= 1.157\times10^{-5} days\\ 1 m/s = \frac {0.001}{1.157\times10^{-5}} km/day = 86.4 km/day \\ 3.0\times 10^{8} m/s = 3.0\times 10^{8} m/s \times \frac {86.4 km/day}{1m/s} =2.592 \times 10^{8}km/day$

7 0

3 years ago

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