The Earth isn't crowded with animals because Humans have overcrowded Earth, but also keep a constant limit with the animal population. However, many species are an endangered species due to the lack of balancing between certain creatures, such as turtles.
I hope this helps!
<h2>
Answer:</h2>
|B| = 47.0 units
<h2>
Explanation:</h2>
The sum of two vectors (A) and (B) gives another vector (A + B). i.e
(A + B) = (A) + (B) ----------------(i)
<em>From the question;</em>
Vector A = 28.0 units in the positive y-direction. This means that the value of the x-component is zero and the value of the y-component is +28
In unit vector notation vector A is given as;
A = 0i + 28.0j
Vector A + B = 19.0 units in the negative y-direction. This means that the value of the x-component is zero and the value of the y-component is -19.0
In unit vector notation, vector A + B is given as;
A + B = 0i - 19.0j
To get the magnitude of vector B, make B the subject of the formula in equation (i) as follows;
(B) = (A + B) - (A) ------------------ (ii)
Substitute the values of the vectors (A) and (A + B) into equation (ii) as follows;
(B) = (0i - 19.0j) - (0i + 28.0j)
(B) = - 19.0j - 28.0j
(B) = - 47.0j
The magnitude of B, |B|, is therefore;
|B| = |-47.0|
|B| = 47.0 units
No. Sadly, you're not right. The whole problem here is the meaning of a few words. "Starts out"is the same thing as "initial" conditions. "At rest" is the same thing as not moving ... zero speed. So if an object starts out at rest, that says that its initial speed is zero ... choice 'b'.
Answer:
The resulting angular speed of the platform is 7.44 rev/s.
Explanation:
Given that,
Speed = 2.4 rev/s
Moment of inertia consist of the man = 6.2 kg-m²
Moment of inertia by the bricks= 2.0 kg-m²
We need to calculate the resulting angular speed of the platform
Using law of conservation of momentum
![L_{1}=L_{2}](https://tex.z-dn.net/?f=L_%7B1%7D%3DL_%7B2%7D)
![I\omega_{1}=I\omega_{2}](https://tex.z-dn.net/?f=I%5Comega_%7B1%7D%3DI%5Comega_%7B2%7D)
![\omega_{2}=\dfrac{I_{1}\omega_{1}}{I_{2}}](https://tex.z-dn.net/?f=%5Comega_%7B2%7D%3D%5Cdfrac%7BI_%7B1%7D%5Comega_%7B1%7D%7D%7BI_%7B2%7D%7D)
Where,
= moment of inertia consist of the man
= moment of inertia by the bricks
= angular speed of platform
Put the value into the formula
![\omega_{2}=\dfrac{6.2\times2.4\times2\pi}{2.0}](https://tex.z-dn.net/?f=%5Comega_%7B2%7D%3D%5Cdfrac%7B6.2%5Ctimes2.4%5Ctimes2%5Cpi%7D%7B2.0%7D)
![\omega_{2}=46.74\ rad/s](https://tex.z-dn.net/?f=%5Comega_%7B2%7D%3D46.74%5C%20rad%2Fs)
![\omega_{2}=\dfrac{46.74}{2\pi}\ rev/s](https://tex.z-dn.net/?f=%5Comega_%7B2%7D%3D%5Cdfrac%7B46.74%7D%7B2%5Cpi%7D%5C%20rev%2Fs)
![\omega_{2}=7.44\ rev/s](https://tex.z-dn.net/?f=%5Comega_%7B2%7D%3D7.44%5C%20rev%2Fs)
Hence, The resulting angular speed of the platform is 7.44 rev/s.