Answer:
2 m/s²
Explanation:
the equations of motion are
S= ut +½at²
v² = u²+ 2as
v = u + at
s = (u+v)/2 × t
From the parameters given
u = 0m/s this is because it starts from rest
Distance (s) = 9m
Time (t) = 3s
Based on this the first equation would be used
s = ut + ½at²
Input values
9 = 0×3 + ½ × a x 3²
9 = 0 + 9a/2
9 = 4.5a
Divide both sides by 4.5
a = 9 / 4.5 m/s²
a = 2 m/s²
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Subtract all numbers to your answer
Answer:
It is likely to be option B: 50 degrees and 50 degrees
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Explanation:
The potential energy is stronger at the start of the bounce and when it is near the end bounce the balls accelerated rate will be lower because the force has decreased . Also I love your profile picture miraculous rocks !
Answer:

Explanation:
Assuming the crate does not lift above the ground and remains along the floor, then its acceleration will be in the horizontal direction. Therefore, we can use Newton's second law to find its acceleration:

where
is the net force on the crate along the x-direction
m is the mass of the crate
is the acceleration
Here we have:
m = 50.0 kg
is the component of the pulling force along the horizontal direction
Solving for the acceleration,
