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3 years ago

The number that describes the main energy level of an electron in an atom is

Physics

1 answer:

Otrada [13]3 years ago

7 0

Answer:

the principal quantum number (n)

Explanation:

Quantum numbers are found in the mathematical description given to each orbital (Schrödinger's wave equation). Schrödinger is the 5th atomic model and it seeks to describe the characteristics of all the electrons in an atom. These digits are represented by letters and each of them indicates the position and energy of each of them.

The main quantum number always has integer and positive numbers and allows us to know the energy level of the orbital as well as its size. N determines the measure of the orbital, so the greater the probability of finding an electron near the nucleus of an atone, the energy of the orbital increases. All those groups of orbitals that share the same value of N are known as level or layer.

The values that the main quantum number (n) can adopt can be positive integers such as: n = 1, 2, 3, 4, 5, 6, 7

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2 years ago

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3 years ago

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3 years ago

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2 years ago

Doss [256]

Answer:

The resultant velocity is <u>169.71 km/h at angle of 45° measured clockwise with the x-axis</u> or the east-west line.

Explanation:

Considering west direction along negative x-axis and north direction along positive y-axis

Given:

The car travels at a speed of 120 km/h in the west direction.

The car then travels at the same speed in the north direction.

Now, considering the given directions, the velocities are given as:

Velocity in west direction is, $\overrightarrow{v_1}=-120\ \vec{i}$

Velocity in north direction is, $\overrightarrow{v_2}=120\ \vec{j}$

Now, since $v_1\ and\ v_2$ are perpendicular to each other, their resultant magnitude is given as:

$|\overrightarrow{v_{res}}|=\sqrt{|\overrightarrow{v_1}|^2+|\overrightarrow{v_2}|^2}$

Plug in the given values and solve for the magnitude of the resultant.This gives,

$|\overrightarrow{v_{res}}|=\sqrt{(120)^2+(120)^2}\\\\|\overrightarrow{v_{res}}|=120\sqrt{2} = 169.71\ km/h$

Let the angle made by the resultant be 'x' degree with the east-west line or the x-axis.

So, the direction is given as:

$x=\tan^{-1}(\frac{|v_2|}{|v_1|})\\\\x=\tan^{-1}(\frac{120}{-120})=\tan^{-1}(-1)=-45\ deg(clockwise\ angle\ with\ the\ x-axis)$

Therefore, the resultant velocity is 169.71 km/h at angle of 45° measured clockwise with the x-axis or the east-west line.

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2 years ago