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Tamiku [17]
4 years ago
15

The number that describes the main energy level of an electron in an atom is

Physics
1 answer:
Otrada [13]4 years ago
7 0

Answer:

the principal quantum number (n)

Explanation:

Quantum numbers are found in the mathematical description given to each orbital (Schrödinger's wave equation). Schrödinger is the 5th atomic model and it seeks to describe the characteristics of all the electrons in an atom. These digits are represented by letters and each of them indicates the position and energy of each of them.

The main quantum number always has integer and positive numbers and allows us to know the energy level of the orbital as well as its size. N determines the measure of the orbital, so the greater the probability of finding an electron near the nucleus of an atone, the energy of the orbital increases. All those groups of orbitals that share the same value of N are known as level or layer.

The values ​​that the main quantum number (n) can adopt can be positive integers such as: n = 1, 2, 3, 4, 5, 6, 7

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.
beks73 [17]

Answer:

2 m/s²

Explanation:

the equations of motion are

S= ut +½at²

v² = u²+ 2as

v = u + at

s = (u+v)/2 × t

From the parameters given

u = 0m/s this is because it starts from rest

Distance (s)  = 9m

Time (t)  = 3s

Based on this the first equation would be used

s = ut + ½at²

Input values

9 = 0×3 + ½ × a x 3²

9 = 0 + 9a/2

9 = 4.5a

Divide both sides by 4.5

a = 9 / 4.5 m/s²

a = 2 m/s²

I hope this was helpful, please mark as brainliest

3 0
4 years ago
HOW do I find 25? *picture included* plz answerrr
pogonyaev
Subtract all numbers to your answer

3 0
3 years ago
This will give brainliest
Troyanec [42]

Answer:

It is likely to be option B: 50 degrees and 50 degrees

Hope it helps.......... pls mark as brainliest.

6 0
3 years ago
Is there a change in speed from when a tennis ball first starts bouncing to when it is near the end of the bounce? How can you t
spin [16.1K]

Explanation:

The potential energy is stronger at the start of the bounce and when it is near the end bounce the balls accelerated rate will be lower because the force has decreased . Also I love your profile picture miraculous rocks !

8 0
3 years ago
A 50.0-kg crate is being pulled along a horizontal smooth surface. The pulling force is 10.0 n and is directed 20.0° above the h
steposvetlana [31]

Answer:

0.188 m/s^2

Explanation:

Assuming the crate does not lift above the ground and remains along the floor, then its acceleration will be in the horizontal direction. Therefore, we can use Newton's second law to find its acceleration:

F_x = ma_x

where

F_x is the net force on the crate along the x-direction

m is the mass of the crate

a_x is the acceleration

Here we have:

m = 50.0 kg

F_x = F cos \theta = (10.0 N)(cos 20.0^{\circ})=9.4 N is the component of the pulling force along the horizontal direction

Solving for the acceleration,

a_x = \frac{F_x}{m}=\frac{9.4}{50.0}=0.188 m/s^2

6 0
4 years ago
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