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rodikova [14]
3 years ago
9

True or false

Physics
1 answer:
Alex Ar [27]3 years ago
8 0
Your answer is true to this question i hope this is correct 

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A ball is tied to the end of a cable of negligible mass. The ball is spun in a circle with a radius 2. 00 m making 7. 00 revolut
mr Goodwill [35]

Answer:

F = M ω^2 R     is the centripetal force on the ball

f = 7 / 10 = .70 / sec      revolutions / sec

ω = 2 pi f = 4.40 / sec

ah = F / m = 4.4^2 * 2 = 38.7 m/s^2

horizontal acceleration = 38.7 m/s^2

vertical acceleration = 9.80 m/s^2

a = (38.7^2 + 9.8^2)^1/2 = 39.9 m/s^2    total acceleration

8 0
2 years ago
What changes would result in a decrease in the gravitational force between two objects? Check all that apply.
REY [17]

<em>I'm sorry, it says check all that apply, however there are no choices given. You should edit, and add the multiple choice answers.</em>

My Answer:

Well if the masses of two objects were both decreased, it would result in a decrease in the gravitational force. So I guess the two objects masses would need to be decreased.

4 0
3 years ago
Paleobotany is the study of fossil insects. True False
alexira [117]

Answer:

False

Explanation:

Paleobotany is the study of fossil plants.

6 0
3 years ago
Read 2 more answers
Why does a light bike have more kinetic energy
FrozenT [24]
Because it doesn't use energy it uses mechanical and kinetic
3 0
3 years ago
A +1.0 nC charge is at x = 0 cm, a -1.0 nC charge is at x = 1.0 cm and a 4.0 nC at x= 2 cm. What is the electric potential energ
lesantik [10]

Answer:

- 2.7 x 10^-6 J

Explanation:

q1 = 1 nC  at x = 0 cm

q2 = - 1 nC at x = 1 cm

q3 = 4 nC at x = 2 cm

The formula for the potential energy between the two charges is given by

U=\frac{Kq_{1}q_{2}}{r}

where r be the distance between the two charges

By use of superposition principle, the total energy of the system is given by

U = U_{1,2}+U_{2,3}+U_{3,1}

U=\frac{Kq_{1}q_{2}}{0.01}+\frac{Kq_{2}q_{3}}{0.01}+\frac{Kq_{3}q_{1}}{0.02}

U=-\frac{9\times10^{9}\times 1\times10^{-9}\times 1\times10^{-9}}}{0.01}-\frac{9\times10^{9}\times 1\times10^{-9}\times 4\times10^{-9}}}{0.01}+-\frac{9\times10^{9}\times 1\times10^{-9}\times 4\times10^{-9}}}{0.02}

U = - 2.7 x 10^-6 J

3 0
3 years ago
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