The total work <em>W</em> done by the spring on the object as it pushes the object from 6 cm from equilibrium to 1.9 cm from equilibrium is
<em>W</em> = 1/2 (19.3 N/m) ((0.060 m)² - (0.019 m)²) ≈ 0.031 J
That is,
• the spring would perform 1/2 (19.3 N/m) (0.060 m)² ≈ 0.035 J by pushing the object from the 6 cm position to the equilibrium point
• the spring would perform 1/2 (19.3 N/m) (0.019 m)² ≈ 0.0035 J by pushing the object from the 1.9 cm position to equilbrium
so the work done in pushing the object from the 6 cm position to the 1.9 cm position is the difference between these.
By the work-energy theorem,
<em>W</em> = ∆<em>K</em> = <em>K</em>
where <em>K</em> is the kinetic energy of the object at the 1.9 cm position. Initial kinetic energy is zero because the object starts at rest. So
<em>W</em> = 1/2 <em>mv</em> ²
where <em>m</em> is the mass of the object and <em>v</em> is the speed you want to find. Solving for <em>v</em>, you get
<em>v</em> = √(2<em>W</em>/<em>m</em>) ≈ 0.46 m/s
It would be option C. It rotates, or spins, on its axis, but it revolves around the sun.
Answer:
The net force acting on the car is
3
×
10
3
Newtons.
Hope this helps you
Explanation:
Force is defined as the product of the mass of the body and its aaceleration,
⇒
F
=
m
a
Substituting the above given values we get,
F
=
(
1500
k
g
)
(
2.0
m
/
s
2
)
=
3000
N
=
3
×
10
3
N
.
Answer:
solids are strong and compact, they are not compressable.
liquids are flexible and less compacts they can not be coompresed
Answer:
The no. of revolutions does the tub turn while it is in motion is = 52.51 revolutions
Explanation:
Given data
= 0
= 5 
Time taken = 7 sec
(1). The angular acceleration is given by
We know that from the equation of motion
-------- (1)
(2). The angular acceleration is given by
- 0.357 
We know that from the equation of motion
= 35.01 rev ------- (2)
Total no of revolution made by the machine is
17.5 + 35.01
52.51 rev
Therefore the no. of revolutions does the tub turn while it is in motion is = 52.51 rev
