All categories

2 years ago

Periods On the periodic table represent elements

1 answer:

7 0

Answer:When you look at the periodic table, each row is called a period (Get it? Like PERIODic table.). All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons.

Explanation:

You might be interested in

Reactants → products

uranmaximum [27]

Answer:

they are equal

Explanation:

the Law of Conservation of Mass states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change

3 0

3 years ago

The hammer, anvil, and stirrup are all bones found in the ear.

AfilCa [17]

Answer: Hammer, anvil and stirrup are small bones in the ear behind ear drum and before cochlea. These bones helps in transfering the vibrations from ear drum to the cochlea which is further passed to auditory nerve and then to brain

Explanation:

4 0

3 years ago

Why does the Moon orbit Earth instead of the Sun?

Vera_Pavlovna [14]

Gravity depends on distance and the moon is closer to earth

4 0

2 years ago

What is the position of an element in the periodic table if its electron configuration is 1s2 2s2 2p6 3s2 3p5

OlgaM077 [116]

The element in the periodic table with the provided electron configuration is Chlorine. Cl it is found as in element in Group 7 of the periodic table.

4 0

3 years ago

Read 2 more answers

Methanol can be produced by the following reaction: CO(g) 2 H2(g) CH3OH(g). How is the rate of disappearance of hydrogen gas rel

belka [17]

Answer:

$r_{H_2}=-2r_{CH_3OH}$

Explanation:

Hello!

In this case, for the reaction:

$CO(g)+ 2 H_2(g) \rightarrow CH_3OH(g)$

In such a way, via the rate proportions, that is written considering the stoichiometric coefficients, we obtain:

$\frac{1}{-1} r_{CO}=\frac{1}{-2} r_{H_2}=\frac{1}{1} r_{CH_3OH}$

Whereas the reactants, CO and H2 have negative stoichiometric coefficients; therefore the rate of disappearance of hydrogen gas is related to the rate of appearance of methanol as shown below:

$\frac{1}{-2} r_{H_2}=\frac{1}{1} r_{CH_3OH}\\\\r_{H_2}=\frac{-2}{1} r_{CH_3OH}\\\\r_{H_2}=-2r_{CH_3OH}$

Which means that the rate of disappearance of hydrogen gas is negative and the rate of appearance of methanol is positive.

Regards!

7 0

3 years ago