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igomit [66]
3 years ago
13

en un recipiente se tiene 800 g de una solución al 35% en masa de ácido sulfuroso, de la cual se evapora 80ml de agua. ¿cuál es

el porcentaje en masa de ácido sulfuroso en la nueva solución? dato: densidad del agua es 1g/ml.
Chemistry
1 answer:
Alinara [238K]3 years ago
5 0

The mass percent of sulfurous acid in the new solution : 38.9%

<h3>Further explanation</h3>

<em>In a container you have 800 g of a 35% by mass solution of sulfurous acid, from which 80 ml of water evaporates. What is the mass percent of sulfurous acid in the new solution? data: density of water is 1g / ml.</em>

<em />

solution 1

composition :

  • 35% acid :

\tt 0.35\times 800~g=280~g

  • water :

\tt 800-280=520~g

solution 2(new solution)

composition :

  • water

\tt 520-(80~ml\times 1~g/ml)=440~g

  • Total mass of new solution after water evaporated

\tt 280(acid)+440(water)=720~g

  • %mass of acid in a new solution

\tt \dfrac{280}{720}\times 100\%=38.9\%

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