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3 years ago

Planets that are larger in diameter, farther from the sun, and less dense then smaller planets in the solar system

2 answers:

5 0

They are actually known as gas giants. Gas giants are large planets that have more than 10 times the mass of Earth, they are also known as the Jovian or Outer planets . Their compositions are a majority of gases, such as hydrogen, and small amounts of rocky material (mostly at their cores). The four gas giants in our solar system are Jupiter, Saturn, Uranus, and Neptune.

nignag [31]3 years ago

3 0

Planets that are larger in diameter, farther from the sun, and less dense then smaller planets in the solar system
are known as giant planets and they are composed of mostly gas like hydrogen gas for example. They are in contradistinction to the terrestrial planets like Mercury Venus Earth and Mars that are solid rock composed of silicate minerals.

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Which type of energy makes the other energy forms possible?

ANEK [815]

Answer:

3. Chemical energy

Explanation:

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3 years ago

The thermal energy of an object is

kompoz [17]

Answer:

The energy contained in its molecules movement and vibration

Explanation:

See above

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3 years ago

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How many moles of CO2 are produced when 1 mole wax C31H64 is burned? 31 32 64 or 47

Lana71 [14]

Answer:

31 moles

Explanation:

The balanced combustion reaction of the wax, $C_{31}H_{64}$ is shown below as:

$C_{31}H_{64}+47O_2\rightarrow 31CO_2+32H_2O$

As seen from the reaction,

1 mole of wax, $C_{31}H_{64}$ on combustion produces 31 moles of carbon dioxide, $CO_2$

Hence, moles of $CO_2$ when 1 mole of wax, $C_{31}H_{64}$ is burnt = 31 moles

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3 years ago

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Which substances can decrease the solubility of CaSO4? how can i identify which substances to use on the solubility table? i sup

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Do not know this answer

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3 years ago

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro

MAVERICK [17]

Answer: The percent yield of water is 46.9 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For sulfuric acid:

Given mass of sulfuric acid = 72.6 g (Assuming)

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfuric acid}=\frac{72.6g}{98g/mol}=0.741mol$

For NaOH:

Given mass of NaOH = 77 g (Assuming)

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaOH}=\frac{77g}{40g/mol}=1.925mol$

The chemical equation for the reaction of sulfuric acid and sodium hydroxide follows:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH

0.741 moles of sulfuric acid will react with = $\frac{2}{1}\times 0.741=1.482mol$ of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent.

Thus, sulfuric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of water

0.741 moles of sulfuric acid will react with = $\frac{2}{1}\times 0.741=1.482mol$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.482 moles

Putting values in equation 1, we get:

$1.482mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.482mol\times 18g/mol)=26.67g$

To calculate the percentage yield of water, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of water = 12.5 g (Assuming)

Theoretical yield of water = 26.67 g

Putting values in above equation, we get:

$\%\text{ yield of water}=\frac{12.5g}{26.67g}\times 100\\\\\% \text{yield of water}=46.9\%$

Hence, the percent yield of water is 46.9 %

3 0

3 years ago