<u>Answer:</u> The total pressure inside the container is 77.9 kPa
<u>Explanation:</u>
Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.
To calculate the total pressure inside the container, we use the law given by Dalton, which is:
We are given:
Vapor pressure of oxygen gas, 
= 40.9 kPa
Vapor pressure of nitrogen gas, 
= 23.3 kPa
Vapor pressure of argon, 
= 13.7 kPa
Putting values in above equation, we get:
Hence, the total pressure inside the container is 77.9 kPa
The pressure of the oxygen gas collected : 718 mmHg
<h3>Further explanation</h3>
Given
P tot = 748 mmHg
P water vapour = 30 mmHg
Required
P Oxygen
Solution
Dalton's law of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases
Can be formulated:
P tot = P1 + P2 + P3 ....
The partial pressure is the pressure of each gas in a mixture
P tot = P H₂O + P Oxygen
P Oxygen = 748 mmHg - 30 mmHg
P Oxygen = 718 mmHg
Answer:
d. Adding 5% HCl solution to the crude reaction mixture will protonate aniline increasing its solubility in the aqueous solution.
Explanation:
On this case, we have to check the <u>structures of each compound</u> (figure 1). For naphthalene we dont have <u>any functional groups</u> therefore, the addition of HCl or NaOH it will not affect naphthalene so <u>we can discard "B" and"C".</u>
When we add HCl solution we will have the production 
the presence of this <u>hydronium ion will protonate the acid</u>, so we can <u>discard a.</u>
<u />
Finally, for d when we add the <u>hydronium ion will react with aniline</u> (a base) and will produce an <u>ammonium ion</u>. This ammonium ion have a <u>positive charge</u>, therefore the <u>polarity will increase</u> and the molecule would be more soluble on water (figure 2).
I hope it helps!
<u>Answer</u>:
mass of magnesium oxide is 4.2 grams.
<u>Explanation</u>:
Balanced equation: 2Mg + O2 → 2MgO.
Given that 2.5 g Mg reacts with 3.0 g O2
- mass = moles * Mr
- moles = mass/Mr
- Mr = mass/moles
First find the moles of Mg:
moles = mass/Mr
moles = 2.5/ 24
moles = 0.104 moles
Using molar ratio, magnesium oxide will have same moles as Mg as they both have "2" molar ratio. So moles of Mg is 0.104 moles.
mass = moles * Mr
mass = 0.104 * 40
mass - 4.1667 g
mass = 4.2 g ___________this is the mass of MgO
