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When the alpha particle hits the beryllium atoms at high speeds, it splits the atomic nuclei hence causing the nuclei particles flying. When exposed to an electric field, the path of the proton is curved towards the negative pole while neutrons are unaffected.
Explanation:
Neutrons are found in the dense part of atoms (the nucleus) along with protons. Unlike protons, however, that are positively charged, neutrons are uncharged particles. Neutrons are important in the stability of the atomic nuclei because they ensure that the positively charged particles (protons), which are cramped together in a tight space, do not repel each other because like-charges repel.
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For more on neutrons check out;
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Isnt the basic particle that all elements are made of electrons because i know that you can get isotopes which is a whole different subject
When a 0. 1 m aqueous solution of hydrocyanic acid, HCN, reaches equilibrium, the ka for hydrocyanic acid is 3.969 x 10⁻¹⁰.
<h3>What is ka value?</h3>
It's the value of equilibrium constant for the dissociation of ions into a solution. The more the Ka value the more will be dissociation.
Ka = [H₃O⁺]² / [HCN] [H₃O⁺]
The pH is 5.20
-log [H₃O⁺] = 5.20
Putting antitlog both side.
The value will be 6.30 x 10⁻⁶
Ka = (6.30 x 10⁻⁶)² / 0.1 - 6.30 x 10⁻⁶
0.1 - 6.30 x 10⁻⁶ = 0.1
Ka = 3.969 x 10⁻¹⁰
Thus, the Ka value for hydrocyanic acid is 3.969 x 10⁻¹⁰.
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Answer:1. ![Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=Rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. The rate constant (k) for the reaction is 
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![rate=k[CHCl_3]^x[Cl_2]^y](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5Ex%5BCl_2%5D%5Ey)
k= rate constant
x = order with respect to 
y = order with respect to 
n = x+y= Total order
1. a) From trial 1: ![0.0035=k[0.010]^x[0.010]^y](https://tex.z-dn.net/?f=0.0035%3Dk%5B0.010%5D%5Ex%5B0.010%5D%5Ey)
(1)
From trial 2: ![0.0069=k[0.020]^x[0.010]^y](https://tex.z-dn.net/?f=0.0069%3Dk%5B0.020%5D%5Ex%5B0.010%5D%5Ey)
(2)
Dividing 2 by 1 :![\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0069%7D%7B0.035%7D%3D%5Cfrac%7Bk%5B0.020%5D%5Ex%5B0.010%5D%5Ey%7D%7Bk%5B0.010%5D%5Ex%5B0.010%5D%5Ey%7D)
therefore x=1.
b) From trial 2: (3)
From trial 3: ![0.0098=k[0.020]^x[0.020]^y](https://tex.z-dn.net/?f=0.0098%3Dk%5B0.020%5D%5Ex%5B0.020%5D%5Ey)
(4)
Dividing 4 by 3:![\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0098%7D%7B0.0069%7D%3D%5Cfrac%7Bk%5B0.020%5D%5Ex%5B0.020%5D%5Ey%7D%7Bk%5B0.020%5D%5Ex%5B0.010%5D%5Ey%7D)
therefore 
![rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. to find rate constant using trial 1:
![0.0035=k[0.010]^1[0.010]^\frac{1}{2}](https://tex.z-dn.net/?f=0.0035%3Dk%5B0.010%5D%5E1%5B0.010%5D%5E%5Cfrac%7B1%7D%7B2%7D)
Answer:
I'm not the best at chemistry but from what I remember you need to balance the equation and you need the arrows. It wants you to use double displacement and so thats the definition im assuming.
Explanation:
An example would be
Na2SO4 + SrCl2 --> 2 NaCl + SrSO4
This is a balanced equation.
https://en.intl.chemicalaid.com/tools/equationbalancer.php
This link will help you balance an equation.
Hopefully this helps I appologize if it doesn't.
