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3 years ago

All camels are basically similar in structure. They have developed adaptations for

Chemistry

1 answer:

Feliz [49]3 years ago

5 0

Answer:

B. Camels’ ears are lined with fur to keep out sand and other blowing matter.

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Can u guys pls write a little paragrapgh for each number hurry pls i need to pass this class for my mom

marin [14]

What the person above said is correct

5 0

3 years ago

2AI + 3H2SO4 -> Al2(SO4)3 + 3H2

podryga [215]

Answer:

B. 313.8

Explanation:

6 0

3 years ago

Which of the following was not a contribution by Niels Bohr? Quantum energy emissions. The charge of an electron. There is a rel

borishaifa [10]

Out of the given options, the charge of an electron was not contributed by Neils Bohr.

Answer: Option 2

<u>Explanation: </u>

The electron's charge was determined by using oil drop experiments performed by Millikan. While Neil Bohr suggested that electrons are rotating in discrete energy levels termed as orbits.

The hydrogen model of Neil Bohr dealt with the quantum energy emission when electron excite from higher energy level to lower energy level. He also stated that there is a relationship between the outer shell and the chemical properties of elements.

So, the second option that is the charge of an electron is not contributed by Bohr as it was contributed by Millikan.

6 0

3 years ago

A Gas OCCUPIES 525ML AT A PRESSURE OF 85.0 kPa WHAT WOULD THE VOLUME OF THE GAS BE AT THE PRESSURE OF 65.0 kPa

german

Boyle's law of ideal gas: This law states that the volume of a gas is inversely proportional to its pressure at a constant temperature. Acc to this law we can write the relation of pressure and volume as:

$PV=Constant$

That means:

$P_{1}V_{1}=P_{2}V_{2}$

From that equation we can calculate Volume of gas at a certain pressure:

P₁=Initial pressure

V₁=Initial volume

P₂=Final pressure

V₂= Final volume

Here P₁, initial pressure is given as 85.0 kPa

V₁, initial volume is given as 525 mL

P₂, final pressure is 65.0 kPa

$P_{1}V_{1}=P_{2}V_{2}$

so,

V_{2}=85\times 525\div 65

=686 mL

Volume of gas will be 686 mL.

8 0

3 years ago

Read 2 more answers

Ethylene (C2H4) is the starting material for the preparation of polyethylene. Although typically made during the processing of p

Solnce55 [7]

Answer:

1.17 grams

Explanation:

Let's consider the balanced equation for the combustion of ethylene.

C₂H₄(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(l)

We can establish the following relations:

1411 kJ are released (-1411 kJ) when 1 mole of C₂H₄ burns.
The molar mass of C₂H₄ is 28.05 g/mol.

The grams of C₂H₄ burned to give 59.0 kJ of heat (q = -59.0 kJ) is:

$-59.0kJ.\frac{1molC_{2}H_{4}}{-1411kJ} .\frac{28.05gC_{2}H_{4}}{1molC_{2}H_{4}} =1.17gC_{2}H_{4}$

8 0

3 years ago