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vladimir2022 [97]
3 years ago
9

A solution contains AgNO3 and Ba(NO3)2. What substance could be added to the solution to precipitate Ag ions, but leave Ba2 ions

in solution
Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

A salt containing chloride ions or hydrochloric acid.

Explanation:

Hello,

In this case, by adding a chloride-based salt or hydrochloric acid, precipitation of silver chloride could be attained by cause of its neglectable solubility in water as shown below:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Moreover, barium chloride is highly soluble in water, for that reason it remains in aqueous solution as specified:

Ba^{2+}(aq)+2Cl^-(aq)\rightarrow BaCl_2(aq)

BaCl_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)

Best regards.

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In a constant‑pressure calorimeter, 60.0 mL of 0.300 M Ba ( OH ) 2 was added to 60.0 mL of 0.600 M HCl . The reaction caused the
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Answer:

Q sln = 75.165 J

Explanation:

a constant pressure calorimeter:

  • Q sln = mCΔT

∴ m sln = m Ba(OH)2 + m HCl

∴ molar mass Ba(OH)2 = 171.34 g/mol

∴ mol Ba(OH)2 = (0.06 L)(0.3 mol/L) = 0.018 mol

⇒ mass Ba(OH)2 = (0.018 mol)(171.34 g/mol) = 3.084 g

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∴ mol HCl = (0.06 L)(0.60 mol/L) = 0.036 mol

⇒ mass HCl = (0.036 mol)(36.46 g/mol) = 1.313 g

⇒ m sln = 3.084 g + 1.313 g = 4.3966 g

specific heat (C):

∴ C sln = C H2O = 4.18 J/g°C

∴ ΔT = 26.83°C - 22.74°C = 4.09°C

heat absorbed (Q):

⇒ Q sln = (4.3966 g)(4.18 J/g°C)(4.09°C)

⇒ Q sln = 75.165 J

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