A solution contains AgNO3 and Ba(NO3)2. What substance could be added to the solution to precipitate Ag ions, but leave Ba2 ions
1 answer:
Answer:
A salt containing chloride ions or hydrochloric acid.
Explanation:
Hello,
In this case, by adding a chloride-based salt or hydrochloric acid, precipitation of silver chloride could be attained by cause of its neglectable solubility in water as shown below:
Moreover, barium chloride is highly soluble in water, for that reason it remains in aqueous solution as specified:
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Answer:
Option A (9.0) is the correct alternative.
Explanation:
The given values are:
Molarity,
= 1.5 M
Volume,
= 6000 mL
or,
= 6 L
As we know,
⇒
or,
⇒
By putting the values, we get
Answer: 12
Explanation.
This problem was recently posted and deals with the conversion of units,so I give the same answer.
You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.
The conversion of units is easily undertaken once you build your conversion factors.
Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.
Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.
Then, build your conversion factor from the definitions given:
- 12 sleps is equal to 9 quibs.
- 12 sleps = 9 quibs
- in virtue of the division property of equality, you can divide both sides by 12 sleps and get:
1 = 12 sleps / 9 quibs ← conversion factor
Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:
- identity property: 9 quibs = 9 quibs × 1
- substitution property: 9 quibs = 9 quibs × 12 sleps/ 9 quibs
You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.
So, all you have to do now is the operations with the numbers:
9 quibs = (9 × 12 / 9) sleps = 12 sleps ← answer