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vladimir2022 [97]
3 years ago
9

A solution contains AgNO3 and Ba(NO3)2. What substance could be added to the solution to precipitate Ag ions, but leave Ba2 ions

in solution
Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

A salt containing chloride ions or hydrochloric acid.

Explanation:

Hello,

In this case, by adding a chloride-based salt or hydrochloric acid, precipitation of silver chloride could be attained by cause of its neglectable solubility in water as shown below:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Moreover, barium chloride is highly soluble in water, for that reason it remains in aqueous solution as specified:

Ba^{2+}(aq)+2Cl^-(aq)\rightarrow BaCl_2(aq)

BaCl_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)

Best regards.

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Explanation:

The pH is a 1 to 14 scale that measures how acidic or basic is a solution, at lowest number the solution will be acid, in 7 the solution will be neutral, and in higher values will be basic. It is a  logarithmic scale, so with each number you move, the acidity or basicity will be increased by a factor of 10. So, lemon juice is more acidic than orange juice by a factor of 100.

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A sample of magnesium oxide has a mass of 94.4 g. How many molecules
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Explanation: molar mass MgO 40.204

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In your own words, explain how gametes (the cells made for sexual reproduction) differ from normal body cells.
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If we start with 8000 atoms of radium-226 how much would remain after 3200 years?
olya-2409 [2.1K]
<h3>Answer:</h3>

2000 atoms

<h3>Explanation:</h3>

We are given the following;

Initial number of atoms of radium-226 as 8000 atoms

Time taken for the decay 3200 years

We are required to determine the number of atoms that will remain after 3200 years.

We need to know the half life of Radium

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n = 3200 years ÷ 1600 years

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Therefore;

Remaining amount = 8000 atoms × 0.5^2

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Thus, the number of radium-226 that will remain after 3200 years is 2000 atoms.

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