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3 years ago

What is the length of a diagonal of a square that is 6 inches on each side

Mathematics

1 answer:

lubasha [3.4K]3 years ago

6 0

Answer:

The answer is 6√2 inches

Step-by-step explanation:

Let

c = diagonal

a and b the sides of the square

c² = a² + b²

c = √(a² + b²)

c = √(6² + 6²)

c = √72

c = √(36 • 2)

c = 6√2

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A 1939 Ford heads out of town traveling at 40 mph. Three hours later a 1957 Chevy follows traveling at 70 mph. How long will it

slavikrds [6]

4 hours

using the formula

distance = speed × time (t)

the Ford will have travelled 3 × 40 = 120 miles before the Chevy leaves

the Ford's distance can be modelled as

distance = 40t + 120

the Chevy's distance can be modelled as

distance = 70t

equating the right sides and solve for t

70 t = 40t + 120 ( subtract 40t from both sides )

30t = 120 ( divide both sides by 30 )

t = 4

the Chevy catches up with the Ford after 4 hours

7 0

3 years ago

WILL MARK BRAINLIEST IF ANSWERED CORRECTLY (SHOW YOUR WORK)

damaskus [11]

Answer:

One solution -> x = 35 , y = -25

Step-by-step explanation:

Solve the following system:

{14 x + 7 y = 315 | (equation 1)

16 x - 2 y = 610 | (equation 2)

Swap equation 1 with equation 2:

{16 x - 2 y = 610 | (equation 1)

14 x + 7 y = 315 | (equation 2)

Subtract 7/8 × (equation 1) from equation 2:

{16 x - 2 y = 610 | (equation 1)

0 x+(35 y)/4 = (-875)/4 | (equation 2)

Divide equation 1 by 2:

{8 x - y = 305 | (equation 1)

0 x+(35 y)/4 = -875/4 | (equation 2)

Multiply equation 2 by 4/35:

{8 x - y = 305 | (equation 1)

0 x+y = -25 | (equation 2)

Add equation 2 to equation 1:

{8 x+0 y = 280 | (equation 1)

0 x+y = -25 | (equation 2)

Divide equation 1 by 8:

{x+0 y = 35 | (equation 1)

0 x+y = -25 | (equation 2)

Collect results:

Answer: x = 35 , y = -25

6 0

3 years ago

Use the theorem in Sec. 28 to show that if f (z) is analytic and not constant throughout a domain D, then it cannot be constant

alexandr1967 [171]

Answer:

The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.

Step-by-step explanation:

Given

For any given function f(z), it is analytic and not constant throughout a domain D

To Prove

The function f(z) is non-constant constant in the neighbourhood lying in D.

Proof

1-Assume that the value of f(z) is analytic and has a constant throughout some neighbourhood in D which is ω₀

2-Now consider another function F₁(z) where

F₁(z)=f(z)-ω₀

3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.

4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.

5-Replacing value of F₁(z) in the above gives:

F₁(z)≡0 in domain D

f(z)-ω₀≡0 in domain D

f(z)≡0+ω₀ in domain D

f(z)≡ω₀ in domain D

So this indicates that the value of f(z) for all values in domain D is a constant ω₀.

This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.

6 0

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP FAST IT'S ASAP

Rzqust [24]

Answer:

572.3

Step-by-step explanation:

Diameter = 27m

Radius = d / 2 = 27 / 2 = 13.5m

Area = pi x r²

= 3.14 x (13.5)²

= 3.14 × 182.25

= 572.3

5 0

3 years ago

Least to greatest. 5 1/2,5 1/4,5 2/3,5 3/8. Please help

Ostrovityanka [42]

5 1/4, 5 3/8, 5 1/2, and 5 2/3

4 0

3 years ago

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