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astraxan [27]
2 years ago
11

A student of 4 feet tall went for swimming in a pool. He saw the depth of water in the pole less than 4 feet .Will he sink , wri

te with reason
Physics
1 answer:
Nataly_w [17]2 years ago
3 0

Answer:

he will not be drowned

Explanation:

Question says , the height of the student = 4 feet,

Depth of the pool( in feet ) be x ( say ) which is less than  4 feet,

Clearly, the depth of the pool < height of the student,

This means, if the student goes for swimming in the pool, however he does not know swimming, he will not be drowned until he is suffering from an injury or external force.

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Where on the Earth would you have to be to see the North Celestial Pole exactly halfway between your horizon and zenith?
mario62 [17]

Answer:

The point straight overhead on the celestial sphere for any observer is called the zenith and is always 90 degrees from the horizon. The arc that goes through the north point on the horizon, zenith, and south point on the horizon is called the meridian.

From any location on Earth you see only half of the celestial sphere, the half above the horizon.

If you stood at the North Pole of Earth, for example, you would see the north celestial pole overhead, at your zenith. The celestial equator, 90° from the celestial poles, would lie along your horizon.

4 0
3 years ago
What do you wish you had learned is Digital Citizenship class?
nydimaria [60]

Answer:

I wish I learned what I could do in the real world with the information I learned

Explanation:

7 0
2 years ago
A boy reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 m above the ground as he rele
kirill115 [55]

Explanation:

It is given that,

Speed of the ball, v = 10 m/s

Initial position of ball above ground, h = 20 m

(a) Let H is the maximum height reached by the ball. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh'            

h'=\dfrac{v^2}{2g}

h'=\dfrac{(10)^2}{2\times 9.8}

h' = 5.1 m

The maximum height above ground,

H = 5.1 + 20

H = 25.1 meters

So, the maximum height reached by the ball is 25.1 meters.

(b) The ball's speed as it passes the window on its way down is same as the initial speed i.e. 10 m/s.

Hence, this is the required solution.                              

6 0
3 years ago
10. What is momentum of the water bottle before the collision? (read the
Alona [7]

Answer:

O ksm/s

Explanation:

before collision,

Velocity =0

So,momentum of the bottle before collision=mass ×velocity

=mass×0

=0 kgm/s

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2 years ago
Researchers condition a flatworm to contract when exposed to light by repeatedly pairing the light with electric shock. the elec
Serga [27]
Negative Reinforcement
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