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kobusy [5.1K]
3 years ago
9

What is the velocity of a 30-kg box with a kinetic energy of 6,000 J? 64 m/s

Physics
1 answer:
Nikolay [14]3 years ago
8 0

Answer: 20 m/s

Explanation: To solve this problem we have to consider the expression of the kinetic energy given by:

Ekinetic=(1/2)*(m*v^2)

then E=0.5*30Kg*(20 m/s)^2=15*400=6000J

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A sailfish swims 120 km/hr. How far will it travel in 8.0 minutes?
Rasek [7]

Answer:

16km

Explanation:

First change the minutes into hours then multiply by the distance.

(8÷60)×120=16km

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4 years ago
What is being transferred as you do work?<br> A. Energy<br> B. Power<br> C. Heat<br> D. Strength
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\huge\bold{\purple{\bold{⚡A. Energy⚡}}}

\huge\underline\mathtt\colorbox{cyan}{Reason:}

When a force causes a body to move, work is done on the object by the force. Work is the measure of the energy transfer when a force 'F' moves an object through a distance 'd'. So we say that energy is transferred from one energy store to another when work is done, and therefore, energy transferred = work done.

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3 years ago
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WHAT IS THE DENSTY OF ALL THE LAYER IN THE ATMOSPHERE
Verdich [7]

Answer:

The troposphere starts at the Earth's surface and extends 8 to 14.5 kilometers high (5 to 9 miles). This part of the atmosphere is the most dense. Almost all weather is in this region.

Explanation:

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3 years ago
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Why do you think the standards changed over time?
Eddi Din [679]

Answer:

https://www.quora.com/Why-do-you-think-standards-of-beauty-have-changed-over-the-years

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your answer is in this link

7 0
4 years ago
An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 34.5
Inessa05 [86]

Answer:

the acceleration of the airplane is 5.06 x 10⁻³ m/s²

Explanation:

Given;

initial velocity of the airplane. u = 34.5 m/s

distance traveled by the airplane, s = 46,100 m

final velocity of the airplane, v = 40.7 m/s

The acceleration of the airplane is calculated from the following kinematic equation;

v² = u² + 2as

2as= v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{(40.7)^2 -(34.5)^2}{2 \times 46,100} \\\\a = 5.06 \ \times \ 10^{-3} \ m/s^2

Therefore, the acceleration of the airplane is 5.06 x 10⁻³ m/s²

5 0
3 years ago
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