Answer:
Explanation:
angular acceleration α = 6.61 / 8.97 = .737 rad / s²
moment of inertia = 1/3 m L²
= 1/3 x 1.13 x .899²
= .3045 kg m²
torque applied = moment of inertia x angular acceleration
= .737 x .3045 = .2244
If be the force
Torque
= F x .899 = .2244
F = .25 N ,
Answer:
descriptive
Explanation:
In this scenario, Amanda would use descriptive statistics in order to present the raw data. That is because, this type of statistic fulfills her goal of summarizing the raw data, while still providing clear and accurate quantitative analysis regarding the different features of the study through the different tests done. Including the personality scales and creativity test data. Since this provides such information it would best fit the goal of what Amanda is trying to accomplish.
Answer:
I = 20 A
Explanation:
The question says that, "A load of 6,000 C is conducted through a cross section in 5 minutes. Determining-if a current is not correct, we will find the value of?"
We have,
Charge, q = 6,000 C
Time, t = 5 minutes = 300 s
We need to find the current. We know that, the charge flowing per unit time is equal to current. So,
So, the current flowing through the circuit is 20 A.
We can use kinematics here if we assume a constant acceleration (not realistic, but they want a single value answer, so it's implied). We know final velocity, vf, is 1.0 m/s, and we cover a distance, d, of 0.47mm or 0.00047 m (1m = 1000mm for conversion). We also can assume that the flea's initial velocity, vi, is 0 at the beginning of its jump. Using the equation vf^2 = vi^2 + 2ad, we can solve for our acceleration, a. Like so: a = (vf^2 - vi^2)/2d = (1.0^2 - 0^2)/(2*0.00047) = 1,064 m/s^2, not bad for a flea!
Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.
