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ELEN [110]
3 years ago
14

Look at the image and answer the question correctly.

Physics
2 answers:
mart [117]3 years ago
7 0

Answer:

B

Explanation:

Anastaziya [24]3 years ago
5 0

Answer:

V=IR

12=I×2

I=12/2

I=6 ampere.

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Basically it is the difference in velocity divided by the time it takes to make that change.
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3 years ago
A spring with spring constant 33N/m is attached to the ceiling, and a 4.8-cm-diameter, 1.5kg metal cylinder is attached to its l
mylen [45]

Answer:

0.423m

Explanation:

Conversion to metric unit

d = 4.8 cm = 0.048m

Let water density be \who_w = 1000 kg/m^3

Let gravitational acceleration g = 9.8 m/s2

Let x (m) be the length that the spring is stretched in equilibrium, x is also the length of the cylinder that is submerged in water since originally at a non-stretching position, the cylinder barely touches the water surface.

Now that the system is in equilibrium, the spring force and buoyancy force must equal to the gravity force of the cylinder. We have the following force equation:

F_s + F_b = W

Where F_s = kxN is the spring force, F_b = W_w = m_wg = \rho_w V_s g is the buoyancy force, which equals to the weight W_w of the water displaced by the submerged portion of the cylinder, which is the product of water density \rho_w, submerged volume V_s and gravitational constant g. W = mg is the weight of the metal cylinder.

kx + \rho_w V_s g = mg

The submerged volume would be the product of cross-section area and the submerged length x

V_s = Ax = \pi(d/2)^2x

Plug that into our force equation and we have

kx + \rho_w \pi(d/2)^2x g = mg

x(k + \rho_w g \pi d^2/4) = mg

x = \frac{m}{(k/g) + (\rho_w\pi d^2/4)} = \frac{1.5}{(33/9.8) + (100*\pi * 0.048^2/4)} = 0.423 m

6 0
2 years ago
What would you expect to cause a drop in air pressure?
Murrr4er [49]

Answer:

D

Explanation:

6 0
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A is the only logical answer
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Why does sodium form an ion +1 charge?
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           hope it will help you and please get my answer in brainlist
                        "i should be thankfull of you"
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