3 years ago

Look at the image and answer the question correctly.

Physics

2 answers:

mart [117]3 years ago

7 0

Answer:

Explanation:

Anastaziya [24]3 years ago

5 0

Answer:

V=IR

12=I×2

I=12/2

I=6 ampere.

You might be interested in

Dana has a sports medal suspended by a long ribbon from her rearview mirror. As she accelerates onto the highway, she notices th

ivann1987 [24]

Answer:

$2.26m/s^2$

Explanation:

Suppose the tension in the ribbon is T.

The upwards component of the tension = Tcos13

The horizontal component of the tension = Tsin13

The weight of the medal = mg

In a vertical direction, mg is balanced by Tcos13, so mg=Tcos13, so T = mg/cos13. The horizontal component of T is the force causing m to accelerate.

$F = ma\\T\sin13^{\circ} = ma$

Substituting T= mg/cos13 gives:

$\frac{mg}{cos13^{\circ}}sin13^{\circ} = ma$

$m$ cancels and you have

$g\tan13 = a\\a=9.81\tan13^{\circ} \approx 2.26m/s^2$

7 0

4 years ago

Within which type of system is the total mass conserved but not the total energy

natulia [17]

Answer:

this could be called an open system.

5 0

3 years ago

As the distance between two point charges is tripled, the electrostatic force between the charges will become

MatroZZZ [7]

Relation between electrostatic force and distance is inverse square i.e
1
Fα ----
r^2

Hence if r is tripled, new electrostatic force will be 1/9 times old force.

7 0

4 years ago

Which of the following statements is true?

Alborosie

My guess is A. I'm not 100% positive but i'm pretty sure.

8 0

3 years ago

Suppose that aliens from a planet orbiting Betelgeuse have eyes similar to human eyes, except that the diameter of their pupils

slega [8]

Answer:

Answered

Explanation:

The data given in the problem

Diameter of a human pupil=0.007 m=7 mm

Diameter of alien pupil=0.5=500 mm

Here we have to calculate the minimum distance at which the alien can see Betelgeuse i.e. the focal length (or the working distance). For this calculation we assume the eye to be a spherical lens.

The focal length and diameter of the lens are related by the formula $F=\frac{r}{2}$ Where r is radius of curvature i.e. d/2

Therefore for the alien, focal length= $F=\frac{25}{2}=12.5mm=0.0125F=\frac{25}{2}$ =12.5mm=0.0125

7 0

3 years ago