Taking into account the definition of avogadro's number, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.
<h3>
Avogadro's Number</h3>
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
<h3>This case</h3>
Then you can apply the following rule of three: if 6.023×10²³ particles are contained in 1 mole of H, then 2.3×10²¹ particles are contained in how many moles of H?
amount of moles of H= (2.3×10²¹ particles × 1 mole)÷ 6.023×10²³ particles
<u><em>amount of moles of H= 3.82×10⁻³ moles</em></u>
Finally, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.
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Answer:
Option 2. 50 %
Explanation:
Reaction: 2HgO (s) → 2Hg (l) + O₂(g)
Ratio is 2:2, 2 moles of mercury oxide produce 2 moles of liquid mercury.
If you produced 1 mol of Hg, then the percent yield reaction is 50%
Percent yield is:
[Produced yield (what you produced) / Theoretical yield (what you excpected to be produced)] . 100 → (1 mol of Hg / 2 mol of Hg) .100 = 50%
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Answer:
Explanation:
CO₂ (aq) + H₂O (l) ⇄ H₂CO₃ (aq)
Equilibrium constant
Kc = [H₂CO₃] / [CO₂] [H₂O]
B )
PCl₃(g) + Cl₂(g) <--> PCl₅(g)
Kc = 24.3 .
[PCl₃] = .10M ,
[Cl₂] = 0.15 M
[PCl₅] = 0.60 M.
Qc = [PCl₅] / [PCl₃] [Cl₂]
= .60 / .10 x .15
= 40
Qc > Kc
Hence the reaction will proceed from left to right to reach equilibrium . It is so because the product concentration is more .
Option C is the right choice .
Answer:
<h3>
<u>C</u><u>.</u><u> </u><u>Fluori</u><u>ne</u><u>.</u></h3>
<u>has</u><u> </u> a small atomic radius.