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3 years ago

Name two functional groups that contain ionic charges?

Chemistry

1 answer:

Alika [10]3 years ago

6 0

The answer is:

carboxylate

and protonated amines

The explanation:

when

The Carboxylic acids are polar . and the functional group carboxyl is formed from the hydroxyl and carbonyl group.

and about protonated amines:

-alkyl groups improve the basicity, aryl groups diminish it.

-Primary amides have an aromatic group or alkyl attached to an amino-carbonyl function.

- Primary amines are basic functions which could be protonated to the ammonium ion

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The entropy of vaporization of water is 109.0 j/mol × k at its normal boiling point. what is the enthalpy of vaporization of wat

riadik2000 [5.3K]

The entropy of a system can be calculated by the ratio of the total heat in the system and the temperature. Entropy is a measure used in thermodynamics to approximate the degree of disorder in a system. From the equation for entropy, we can calculate the enthalpy as follows:

S = H / T
109.0 J / mol K = H / 373.15 K
H = 40673.35 J / mol

3 0

3 years ago

30,000 J of heat are added to 23.0 kg of steel to reach a final temperature of 140

kolbaska11 [484]

The initial temperature is 137.34 °C.

<u>Explanation:</u>

As the specific heat formula says that the heat energy required is directly proportional to the mass and change in temperature of the system.

Q = mcΔT

So, here the mass m is given as 23 kg, the specific heat of steel is given as c = 490 J/kg°C and the initial temperature is required to find with the final temperature being 140 °C. Also the heat energy required is 30,000 J.

ΔT = $\frac{Q}{mc}$

ΔT = $\frac{30000}{23 \times 490} = \frac{30000}{11270} =2.66$

Since the difference in temperature is 2.66, then the initial temperature will be

Final temperature - Initial temperature = Change in temperature

140-Initial temperature = 2.66

Initial temperature = 140-2.66 = 137.34 °C

Thus, the initial temperature is 137.34 °C.

7 0

4 years ago

What is the mole-to-mole ratio between N2 and H2?

spin [16.1K]

Remember, look at the coefficients in the balanced equation! Here are three mole ratios:
1 mole<span> N2 / </span>3 moles<span> H2.</span>
3 moles<span> H2 / 2 moles NH3.
</span>

5 0

3 years ago

Dinitrogen pentoxide is used in the preparation of explosives. If 7.93 mol of

Tpy6a [65]

The volume of O₂ produced: 84.6 L

<h3>Further explanation</h3>

Given

7.93 mol of dinitrogen pentoxide

T = 48 + 273 = 321 K

P = 125 kPa = 1,23365 atm

Required

Volume of O₂

Solution

Decomposition reaction of dinitrogen pentoxide

2N₂O₅(g)→4NO₂(g)+O₂ (g)

From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :

= 0.5 x mol N₂O₅

= 0.5 x 7.93

= 3.965 moles

The volume of O₂ :

$\tt V=\dfrac{nRT}{P}\\\\V=\dfrac{3.965\times 0.082\times 321}{1.23365}\\\\V=84.6~L$

5 0

4 years ago

Beryllium oxide, Beo, is an electrical insulator. How

egoroff_w [7]

Answer:

There are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.

Explanation:

We can calculate the number of moles (η) of BeO as follows:

$\eta = \frac{m}{M}$

Where:

m: is the mass = 250 g

M: is the molar mass = 25.0116 g/mol

Hence, the number of moles is:

$\eta = \frac{250 g}{25.0116 g/mol} = 10.0 moles$

Therefore, there are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.

I hope it helps you!

3 0

3 years ago