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maxonik [38]
3 years ago
7

Among the following, which is an oxidation-reduction reaction? Question 13 options: Na2S + CaCO3 → CaS + Na2CO3 2HNO3 + Mg(OH)2

→ Mg(NO3)2 + 2H2O H2 + F2 → 2HF 3Ba(OH)2 + 2H3PO4 → Ba3(PO4)2 + 6H2O
Chemistry
1 answer:
Tamiku [17]3 years ago
5 0
This one is an oxidation-rdcution equation:

<span>H2 + F2 → 2HF

How can you tell?

If the oxidation states of the atoms in the reactans are different from the oxidation states of the same atoms in the products then it is an oxidation-reduction reaction.

Both atoms H and F in the reactants have oxidation states 0.

That is a basic rule: any atom alone or bonded to the same kind of atom has oxidation state 0.

The oxidation states in HF are: H: +1, and F: -1.

So, the H increased its oxidation state, which is that ii is oxydized ; while F reduced its oxidation state so it is reduced.

Answer: H2 + F2 ----> 2HF
</span>
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Which example indicates that a chemical change has occurred? *
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A. When two aqueous solutions are mixed, a precipitate is formed.

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B) Quelle est la masse de tétraoxyde de trifer (Fe3O4) produite si 3,60 moles de trioxyde de
hram777 [196]

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626,4 g de Fe₃O₄

Explanation:

Nous commencerons par écrire l'équation équilibrée de la réaction entre le fer (Fe) et le trioxyde d'aluminium. Ceci est donné ci-dessous:

9Fe + 4Al₂O₃ -> 3Fe₃O₄ + 8Al

De l'équation équilibrée ci-dessus,

4 moles d'Al₂O₃ ont réagi pour produire 3 moles de Fe₃O₄.

Par conséquent, 3,6 moles d'Al₂O₃ réagiront pour produire = (3,6 × 3) / 4 = 2,7 moles de Fe₃O₄

Ainsi, 2,7 moles de Fe₃O₄ sont produites à partir de la réaction.

Enfin, nous déterminerons la masse massique de Fe₃O₄ produite par la réaction. Ceci peut être obtenu comme suit:

Mole de Fe₃O₄ = 2,7 moles

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= 168 + 64

= 232 g / mol

Masse de Fe₃O₄ =?

Mole = masse / masse molaire

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Croiser multiplier

Masse de Fe₃O₄ = 2,7 × 232

Masse de Fe₃O₄ = 626,4 g

Par conséquent, 626,4 g de Fe₃O₄ sont produits à partir de la réaction

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