Answer:
genotype are the organism's hereditary information for example DNA
phenotype are the organism's physical characteristics for example your eyes or hair
or how your nose looks
Answer: The rates of production of 
is 
mol/Ls and 
is 0.0195 mol/Ls.
Explanation:
Rate with respect to reactants is shown by negative sign as the reactants are decreasing with time and Rate with respect to products is shown by positive sign as the products are increasing with time.
Rate of the reaction=![-\frac{1}{4}\frac{[d[PH_3]}{dt}=\frac{[d[P_4]}{dt}=\frac{1}{6}\frac{[d[H_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B4%7D%5Cfrac%7B%5Bd%5BPH_3%5D%7D%7Bdt%7D%3D%5Cfrac%7B%5Bd%5BP_4%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7B%5Bd%5BH_2%5D%7D%7Bdt%7D)
Rate of decomposition of 
Rate of production of 
Rate of production of 
Answer:
the answer is
<em><u>C. to collect rock samples from the moon</u></em>
I swear I did't copy off of the first person I just took the test and at the end went I completed the test it showed me the real answer.
I hope that this is helpful for you
:D
Answer:c. At 20% efficiency, how many kWh would actually be produced from the 5 gal of gasoline? How many BTUs of heat would be released from burning the gasoline? (3 points) 1.3 x 10 J x 1 kWH / 3.6 x 10 J = 36.1 kWh 5.2 x 10 J x 1 BTU / 1055 J = 492891 BTU 36.1 kWh would actually be produced from 5 gallons of gasoline.
Explanation:
I hope I help
Answer:
When pH = pKa, the ionizable compound in question (either acid or base) will be half protonated and half deprotonated
Explanation:
A convenient way of expressing the relative strength of an acid is by the value of its pKa, which makes it easy to see in small changes in pKa the changes associated with large variations in Ka. Small pKa values are equivalent to large Ka (dissociation constant) values, and as pKa decreases, the strength of the acid increases.
An acid will be stronger the lower its pKa and in a base it happens the other way around, which is stronger the higher its pKa.
Those dissociation constants are not fixed, they depend on other variables. For example, the dissociation constant changes at different temperatures. However, it maintains its value at the same temperature, before changes in the concentration of any of the species or even under the action of a catalyst.
