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maxonik [38]
3 years ago
7

Among the following, which is an oxidation-reduction reaction? Question 13 options: Na2S + CaCO3 → CaS + Na2CO3 2HNO3 + Mg(OH)2

→ Mg(NO3)2 + 2H2O H2 + F2 → 2HF 3Ba(OH)2 + 2H3PO4 → Ba3(PO4)2 + 6H2O
Chemistry
1 answer:
Tamiku [17]3 years ago
5 0
This one is an oxidation-rdcution equation:

<span>H2 + F2 → 2HF

How can you tell?

If the oxidation states of the atoms in the reactans are different from the oxidation states of the same atoms in the products then it is an oxidation-reduction reaction.

Both atoms H and F in the reactants have oxidation states 0.

That is a basic rule: any atom alone or bonded to the same kind of atom has oxidation state 0.

The oxidation states in HF are: H: +1, and F: -1.

So, the H increased its oxidation state, which is that ii is oxydized ; while F reduced its oxidation state so it is reduced.

Answer: H2 + F2 ----> 2HF
</span>
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Calculate the amount of heat needed to boil of benzene (), beginning from a temperature of . Be sure your answer has a unit symb
Pavlova-9 [17]

Answer:

Check explanation

Explanation:

From the question, the parameters given are 64.7g of benzene,C6H6; a starting temperature of 41.9°C and bringing it to 33.2°C.

Molar mass of benzene,C6H6= 78.11236 g/mol.

Things to know: heat capacity of benzene, C6H6= 1.63 J/g.K, the heat of fusion = 9.87 kj/mol.

STEP ONE(1): ENERGY USED IN MELTING BENZENE SOLID.

Using the formula below;

Energy used in melting the solid(in JOULES) = (mass of benzene/molar mass of benzene) × heat of Fusion.

=(64.7 g of C6H6/ 78.11236(g per mol) of C6H6) × 9.87 kJ per mol.

= 8.175 J.

= 0.008175 kJ.

STEP TWO (2): ENERGY OF HEATING THE LIQUID.

It can be calculated from the formula below;

Energy= heat capacity (J/g.K) × mass of benzene× (∆T).

= 1.63 J/g.K × 64.7 × (41.9-33.2).

= 917.5J.

= 0.9175 kJ.

Energy required to boil benzene= Energy required to melt the bezene + energy required for boiling.

= 0.008175+ 0.9175.

= 0.93kJ

Approximately, 1 kJ

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