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Gala2k [10]
3 years ago
12

Acetone, CH3COCH3, is a nonelectrolyte; hypochlorous acid, HClO, is a weak electrolyte; and ammonium chloride, NH4Cl, is a stron

g electrolyte. What are the solutes present in aqueous solutions of each compound? If 0.1 mol of each compound is dissolved in solution, which one contains 0.2 mol of solute particles, which contains 0.1 mol of solute particles, and which contains somewhere between 0.1 and 0.2 mol of solute particles?
Chemistry
1 answer:
natta225 [31]3 years ago
7 0

Answer:

NH4Cl contains 0.2 mol of solute particles, CH3COCH3 contains 0.1 mol of solute particles, and HClO contains somewhere between 0.1 and 0.2 mol of solute particles

Explanation:

Strong electrolyte will dissociate completely and from 2 particles from one. weak electrolyte will form something in between because it won't dissociate completely. And nonelectrolyte won't dissociate at all.

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CO_2 sublimes readily at 25°C. Which properties are usually associated with a compound that undergoes this kind of change?
antoniya [11.8K]

Explanation:

Sublimation is defined as a process in which solid state of a substance directly changes into vapor or gaseous state without undergoing liquid phase.

For example, naphthalene balls show sublimation at room temperature.

As this process does not cause any change in chemical composition of a substance. Hence, it is known as a physical process.

Similarly, when CO_{2} sublimes readily at 25^{o}C. This shows change in physical state of carbon dioxide is taking place, i.e, from solid to gaseous phase.

Thus, we can conclude that when CO_{2} sublimes readily at 25^{o}C then it means physical properties are usually associated with a compound that undergoes this kind of change.

4 0
2 years ago
Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:
Andru [333]

Answer:

gde

Explanation:

We are attempting to synthesize 1-butyne from 1-chlorobutane. Since 1-chlorobutane is a primary alkyl halide, 1-butene is formed when 1-chlorobutane is reacted with a bulky base such as t -BuOK or t -BuOH in presence of strong heat. This is an E2 reaction.

Secondly, the 1-butene is reacted with bromine in carbon tetrachloride. The vicinal dihalide (1,2-dibromobutane) is formed. This can now undergo further elimination reactions in the presence of sodamide and strong heat to yield 1-butyne which is the desired product. These reactions involve the elimination of the first HBr molecule to give an alkenyl bromide. A second elimination now gives the terminal alkyne.

3 0
3 years ago
A sample of 0.370 mol of a metal oxide (m2o3) weighs 55.45 g. how many grams of o are in the sample?
Wewaii [24]
0.370 mol metal oxide = 55.45 g 

<span>1 mol = 55.45/0.370 = 149.86 g </span>

<span>in 1 mol there are 3 mol O = 16 * 3 = 48 g of O </span>

<span>there is 48/149.86 * 100% O in the sample </span>

<span>the sample has 48/149.86 * 0.370 = 0.119 g O</span>
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3 years ago
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3 years ago
3. Mr. Hill has 27 students in his class
stich3 [128]
Just dived both numbers by two
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