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Gala2k [10]
2 years ago
12

Acetone, CH3COCH3, is a nonelectrolyte; hypochlorous acid, HClO, is a weak electrolyte; and ammonium chloride, NH4Cl, is a stron

g electrolyte. What are the solutes present in aqueous solutions of each compound? If 0.1 mol of each compound is dissolved in solution, which one contains 0.2 mol of solute particles, which contains 0.1 mol of solute particles, and which contains somewhere between 0.1 and 0.2 mol of solute particles?
Chemistry
1 answer:
natta225 [31]2 years ago
7 0

Answer:

NH4Cl contains 0.2 mol of solute particles, CH3COCH3 contains 0.1 mol of solute particles, and HClO contains somewhere between 0.1 and 0.2 mol of solute particles

Explanation:

Strong electrolyte will dissociate completely and from 2 particles from one. weak electrolyte will form something in between because it won't dissociate completely. And nonelectrolyte won't dissociate at all.

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A client takes 30 ml of magnesium hydroxide and aluminum hydroxide with simethicone P.O. 1 hour and 3 hours after each meal and
labwork [276]

Answer:

Due to the short term of its action it has in the stomach environment

Explanation:

Aluminum hydroxide, magnesium hydroxide, and simethicone is a combination drug used for the treatment of upset stomach, acid indigestion, bloating heartburn caused by gas, or stomach discomfort caused by eating or drinking too much

4 0
3 years ago
How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?
Kipish [7]

Answer:

V KOH = 41 mL

Explanation:

for neutralization:

  • ( V×<em>C </em>)acid = ( V×<em>C </em>)base

∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ <em>C</em> KOH = 0.0050 N = 0.0050  eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

4 0
2 years ago
How many moles of hydrogen are needed to produce 13.78 mol of ethane?
mamaluj [8]
Ethane is an alkane. Methane is also an alkane and is considered to be the simplest alkane. The difference is ethane has only 2 carbon. That carbon has 6 hydrogen attached to it. So what we do is we multiply the moles of ethane by the number of hydrogen (by dimension analysis) resulting to 82.68 moles H.
4 0
3 years ago
Read 2 more answers
Mount Everest rises to a height of 8,850 m above sea level. At a base camp on the mountain the atmospheric pressure is measured
yan [13]

Answer:

Water will boil at 76^{0}\textrm{C}.

Explanation:

According to clausius-clapeyron equation for liquid-vapor equilibrium:

                                         ln(\frac{P_{2}}{P_{1}})=\frac{-\Delta H_{vap}^{0}}{R}[\frac{1}{T_{2}}-\frac{1}{T_{1}}]

where, P_{1} and P_{2} are vapor pressures of liquid at T_{1} (in kelvin) and T_{2} (in kelvin) temperatures respectively.

Here, P_{1} = 760.0 mm Hg, T_{1} = 373 K, P_{2} = 314.0 mm Hg

Plug-in all the given values in the above equation:

                          ln(\frac{314.0}{760.0})=\frac{-40.7\times 10^{3}\frac{J}{mol}}{8.314\frac{J}{mol.K}}\times [\frac{1}{T_{2}}-\frac{1}{373K}]

                       or, T_{2}=349 K

So, T_{2}=349K=(349-273)^{0}\textrm{C}=76^{0}\textrm{C}

Hence, at base camp, water will boil at 76^{0}\textrm{C}

6 0
3 years ago
A sample of no2 occupies 16,500 ml at stp. How many no2 molecules are in the sample?.
svet-max [94.6K]
here it is! mL to Liters to moles to molecules

6 0
2 years ago
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