Which of these is an example of a physical change ?

What is the wavelength range,in nanometer,for infrared light? In what portion of this range does the earth receive IR from the s

andrezito [222]

The wavelength range of Infrared radiation is 700 nanometers to 1 millimeter.
The sun emits mainly near-infrared which is mainly composed of wavelength below 4 micrometers.
The thermal range of infrared ranges between wavelengths 3.5 and 2.0 micrometers

Explanation:

The wavelength range of Infrared radiation is 700 nanometers to 1 millimeter. This also translates to a frequency range of 430 TeraHertz to 300 Giga Hertz.

Because the sun is a star and is hot in comparison to earth and other planetary bodies, the bigger range of infrared radiation it emits is in the near-infrared which is mainly composed of wavelength below 4 micrometers.

The earth's surface produces infrared radiation of the mid-infrared range while cooler substances will produce far-infrared range

The thermal range of infrared ranges between wavelengths 3.5 and 2.0 micrometers and is produced by black bodies.

Learn More:

For more on infrared radiation check out;

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7 0

3 years ago

Calculate the pressure of 2.50 Liters of a gas at 25.0oC if it has a volume of 4.50 Liters at

MariettaO [177]

Answer:

P_2 =0.51 atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

Volume (V2) = 4.50 L

at standard temperature and pressure;

Pressure (P1) = 1 atm

Temperature (T2) = 273 K

Pressure P2 = ??

Using combined gas law:

$\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}$

$0.008389261745 \times 273 = 4.5P_2$

$P_2 =\dfrac{0.008389261745 \times 273 }{4.5}$

$P_2 =0.51 \ atm$

4 0

2 years ago

Give 1 example of a chemical reaction that is involved in coral<br> bleaching.

const2013 [10]

2HCO3 - + Ca2+ CaCO3 + CO2 + H2O Bicarbonate (HCO3-) combines with calcium ions in the water to make calcium carbonate (CaCO3, limestone). This process can occur both within organisms such as corals or as a simple chemical reaction in the water itself.

3 0

1 year ago

23. The cell has a

andrew11 [14]

Then that would be 100% all together I believe

5 0

9 months ago

A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Ca

umka21 [38]

Answer:

$W = 6.65 \cdot 10^{6} lbf$

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

$W = m\cdot g$ (1)

Where m the mass and g is the gravity

Also, we have that the mass is:

$m = \rho*V$ (2)

Where ρ is the density and V the volume

We cand calculate the volume as follows:

$V = L*w*d$ (3)

Where L is the length, w is the wide and d is the depth

By entering equation (2) and (3) into (1) we have:

$W = \rho*L*w*d*g$

$W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}$

$W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf$

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

6 0

3 years ago