Answer:
B. K+cation
Explanation:
Not all that sure but hope it will help.
The volume of water that will be produced from the reaction will be 6.3 mL
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:

The mole ratio of hydrogen sulfate to sodium hydroxide is 1:2.
Mole of hydrogen sulfate = 0.50 x 350/1000 = 0.175 moles
Mole of 15 grams sodium hydroxide = 15/40 = 0.375 moles
Thus, hydrogen sulfide is the limiting reagent.
Mole ratio of hydrogen sulfide to water = 1:2.
Equivalent mole of water = 0.175 x 2 = 0.35 moles
Mass of 0.35 moles of water = 0.35 x 18 = 6.3 grams.
1 gram of water = 1 ml.
Thus, 6.3 grams of water will be equivalent to 6.3 mL
More on stoichiometric calculation can be found here: brainly.com/question/27287858
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Ans: Final volume = 25.0 ml
<u>Given:</u>
Initial volume V1 = 50.0 ml
Initial pressure P1 = 20.0 atm
Final pressure P2 = 40.0 atm
<u>To determine:</u>
The final volume V2
<u>Explanation:</u>
Ideal gas equation: PV = nRT
under constant temperature, T and number of moles n we have:
PV = constant
or, P1V1 = P2V2
V2 = P1V1/P2 = 20*50/40 = 25 ml.
<span>0.3 liters of volume is required.</span>