Alkanes, alkenes, and alkynes are compounds containing only carbon and hydrogen. When these compounds undergo complete combustion, the products are carbon dioxide and water. Otherwise, when incomplete combustion occurs, carbon dioxide, water, and carbon monoxide are produced. Note that carbon monoxide is a toxic gas that is harmful to people's health.
Molarity is defined as the number of moles of solute in 1 L of solution
mass fo KCl in the solution is - 5.0 g
number of moles of KCl - 5.0 g/ 74.5 g/mol = 0.067 mol
number of moles of KCl in 100 mL - 0.067 mol
therefore number of KCl moles in 1 L - 0.067 / 100 mL x 1000 mL = 0.67 M
molarity of KCl is 0.67 M
Answer:
Option D is correct = 58 g
Explanation:
Data Given:
mass of LiOH = 120 g
Mass of Li3N= ?
Solution:
To solve this problem we have to look at the reaction
Reaction:
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol 3 mol
Convert moles to mass
Molar mass of LiOH = 24 g/mol
Molar mass of Li₃N = 35 g/mol
So,
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol (35 g/mol) 3 mol (24 g/mol)
35 g 72 g
So if we look at the reaction 35 g of Li₃N react with water and produces 72 g of LiOH , then how many g of Li₃N will be react to Produce by 120 g of LiOH
For this apply unity formula
35 g of Li₃N ≅ 72 g of LiOH
X of Li₃N ≅ 120 g of LiOH
By Doing cross multiplication
Mass of Li₃N = 35 g x 120 g / 72 g
mass of Li₃N = 58 g
120 g of LiOH will produce from 58 g of Li₃N
So,
Option D is correct = 58 g
Answer:
0.75L
Explanation:
To get the number of liters of hydrogen gas produced, it is very essential to get the number of moles of hydrogen gas produced.
The number of moles of hydrogen gas produced is obtainable and accessible from
the number of moles of zinc reacted.
Hence, we will get the number of moles of zinc reacted at first. To get the number of moles of zinc reacted, we divide the mass of the zinc by the atomic mass of the zinc metal which is 65.38 amu
The number of moles of the zinc is thus: 2.2/65.38 which equals 0.03365 mole
From the equation of chemical reaction, it can be seen that one mole of zinc metal yielded one mole of hydrogen gas. Hence, it is expected that 0.03365mole of zinc will yield 0.03365mole of hydrogen gas.
Now, we proceed to get the volume of the hydrogen gas produced. We know quite well that at S.T.P a mole of a gas occupies a volume of 22.4L. Hence , 0.03365 mole will occupy a volume of 22.4 * 0.03365 which equals 0.75L
