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3 years ago

How does a squirrel get prepare for the winter months?

Chemistry

1 answer:

Furkat [3]3 years ago

3 0

Answer:

Well, I have pet squirrels, and I know they get acorns and other food, and dig up certain spots on the ground, then put their food in there. And they have food for the winter.

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Enter an equation to show how h2po3− can act as a base with hs− acting as an acid. Express your answer as a chemical equation. I

vladimir2022 [97]

The acid - base equation between H2PO3^- and HS^- is H2PO3^- + HS^- ⇄S^- + H3PO3.

An acid is a substance that can donate hydrogen ions while a base is a substance that can accept hydrogen ion. This is the acid base definition according to Brownstead - Lowry.

To show the acid - base relationship between H2PO3^- and HS^-, we have the equation;

H2PO3^- + HS^- ⇄S^- + H3PO3

Learn more about acids and bases: brainly.com/question/10282816

4 0

2 years ago

In a chemical reaction, 28g of iron reacts with 16g of sulfur to produce _________ of iron sulfide.

kirill115 [55]

Hello!

In a chemical reaction, 28g of iron reacts with 16g of sulfur to produce _________ of iron sulfide.

We have the following data:

m(Fe) - mass of iron = 28 g

m(S) - mass of sufur = 16 g

MM(Fe) - molar mass of iron ≈ 56 g/mol

MM(S) - molar mass of sulfur ≈ 32 g/mol

n(Fe) - number of mol of iron = ?

n(S) - number of mol of sulfur = ?

Solving:

* to n(Fe)

$n_{Fe} = \dfrac{m_{Fe}}{MM_{Fe}}$

$n_{Fe} = \dfrac{28\:\diagup\!\!\!\!\!g}{56\:\diagup\!\!\!\!\!g/mol}$

$\boxed{n_{Fe} = 0.5\:mol}$

* to n(S)

$n_{S} = \dfrac{m_{S}}{MM_{S}}$

$n_{S} = \dfrac{16\:\diagup\!\!\!\!\!g}{32\:\diagup\!\!\!\!\!g/mol}$

$\boxed{n_{S} = 0.5\:mol}$

The stoichiometric reaction will be in the same proportion (1 : 1), let us see:

$Fe + S \Longrightarrow FeS$

1 mol of Fe -------------- 1 mol of FeS

0.5 mol of Fe ------------ 0.5 mol of FeS

Will the reaction of the iron mass with the mass of sulfur produce how many grams of iron sulfide? We will see:

n(FeS) - number of mol of iron sulfide = 0.5 mol

m(FeS) - mass of iron sulfide = ? (in grams)

MM(FeS) - Molar Mass of iron sulfide = 56 + 32 = 88 g/mol

Solving:

$n_{FeS} = \dfrac{m_{FeS}}{MM_{FeS}}$

$m_{FeS} = n_{FeS}*MM_{FeS}$

$m_{FeS} = 0.5\:mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}*88\:\dfrac{g}{mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}}$

$\boxed{\boxed{m_{FeS} = 44\:g}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}$

Answer:

44 grams of iron sulfide

___________________________

$\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

4 0

3 years ago

En la electrosis del cloruro de sodio (Na Ci) el cloruro es atraido por elcatodo. Falso o verdadero. Y porque?

hram777 [196]

Answer:

Falso

Explanation:

La electrólisis es la descomposición de una solución cuando la corriente continua se pasa a través de ella.

La corriente entra y abandona el electrolito a través de los electrodos. El electrodo positivo se llama el ánodo mientras el electrodo negativo se llama cátodo.

Los iones positivos se mueven hacia el cátodo, mientras que los iones negativos se mueven hacia el ánodo.

Dado que el cloruro es un ion negativo, se mueve hacia el ánodo y no hacia el cátodo.

8 0

3 years ago

How many atoms of both elements are there in this molecule: 3N205; O 3 Nitrogen and 15 Oxygen 6 Nitrogen and 5 Oxygen KD 2 Nitro

abruzzese [7]

Answer:

Explanation:

oxygen is a 15 and nitrogen science chemistry i'm guessing

6 0

3 years ago

The "air bags" that are currently installed in automobiles to prevent injuries in the event of a crash are equipped with sodium

stellarik [79]

Answer:

0.0177 L of nitrogen will be produced

Explanation:

The decomposition reaction of sodium azide will be:

$2NaN_{3}(s)--->2Na(s)+3N_{2}(g)$

As per the balanced equation two moles of sodium azide will give three moles of nitrogen gas

The molecular weight of sodium azide = 65 g/mol

The mass of sodium azide used = 100 g

The moles of sodium azide used = $\frac{mass}{molarmass}=\frac{100}{65}=1.54mol$

so 1.54 moles of sodium azide will give = $\frac{3X1.54}{2}=2.31$ mol

the volume will be calculated using ideal gas equation

PV=nRT

Where

P = Pressure = 1.00 atm

V = ?

n = moles = 2.31 mol

R = 0.0821 L atm / mol K

T = 25 °C = 298.15 K

Volume = $\frac{P}{nRT}=\frac{1}{2.31X0.0821X298.15}=0.0177L$

3 0

3 years ago