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Oksi-84 [34.3K]
3 years ago
11

HOW DO I SOLVE 23-PO= .122*PO.

Mathematics
1 answer:
MAXImum [283]3 years ago
7 0

Answer:

Step-by-step explanation:

just solve it heehee

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If your current examination mean is 97.2 and you receive a 99 on the next examination, what effect will this have?
mr Goodwill [35]

If you have an average of 97.2 on your current exam and you get a 99 on your next exam, your average will increase.

  • Mean in mathematics is the sum (total) of all the values in a set of data, such as numbers or measurements, divided by the total number of values.

  • To find the average, sum all the values ​​in the set. Then divide the total by the number of values.

We have the current examination mean, xold = 97.2

Now, we receive,  x = 99 on the next examination, the new mean will be:

xnew = (xold + x)/N

xnew = (97.2+99)/2

xnew = 196.2/2

xnew = 98.1  

The new average is 98.1

98.1 > 97.2

So if you score 99 on your next exam, your average will increase.

Learn more about mean here

brainly.com/question/1136789

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3 0
2 years ago
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Pls can someone help me<br><img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7
Firlakuza [10]

Answer:

= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )

Step-by-step explanation:

Given the expression log10\sqrt{36} + log10\sqrt{2}  - log10\sqrt{7} \\

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

log10\sqrt{36} + log10\sqrt{2}  - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )

6 0
3 years ago
Please help i will mark branliest
kotegsom [21]

Answer:

C

Step-by-step explanation:

5 0
3 years ago
Line / is a straight line.
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Answer:

the first and last one

Step-by-step explanation:

6 0
3 years ago
Tony makes a 5% commission on all his sales If his commission check is for $152.00 then what were Tony’s sales
shepuryov [24]

Answer:

i think its 7.60 but idk for sure

3 0
4 years ago
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