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Viktor [21]
3 years ago
5

100 POINTS. PLEASE PROVIDE EXPLANATION

Physics
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

Expression of Genes. Gene regulation is the process of controlling which genes in a cell's DNA are expressed (used to make a functional product such as a protein).In eukaryotes like humans, gene expression involves many steps, and gene regulation can occur at any of these steps.

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Se coloca una piedra de 600 g en una Honda de 50 cm y se la hace girar a una velocidad de 4 m/s. Dibuja la fuerza que ejerce la
Dima020 [189]

Answer:

Fc = 19.2 N

Explanation:

In this case, the force of the Honda over the rock, is a centripetal force. Then, you have:

F_c=m\frac{v^2}{r}

m: mass of the rock = 600g = 0.6 kg

v: tangential velocity of the Honda = 4m/s

r: radius of the Honda = 50cm = 0.5m

You replace the values of m, r and v in the equation for Fc:

F_c=(0.6kg)\frac{(4m/s)^2}{0.5m}\\\\F_c=19.2N

hence, the force has a magnitude of 19.2 N

If the rock would have more mass the centripetal force would be higher

4 0
3 years ago
A particle starts from rest and has an acceleration function 5 − 10t m/s2 . (a) What is the velocity function? (b) What is the p
frez [133]

Explanation:

It is given that,

A particle starts from rest and has an acceleration function as :

a(t)=(5-10t)\ m/s^2

(a) Since, a=\dfrac{dv}{dt}

v = velocity

dv=a.dt

v=\int(a.dt)

v=\int(5-10t)(dt)

v=5t-\dfrac{10t^2}{2}=5t-5t^2

(b) v=\dfrac{dx}{dt}

x = position

x=\int v.dt

x=\int (5t-5t^2)dt

x=\dfrac{5}{2}t^2-\dfrac{5}{3}t^3

(c) Velocity function is given by :

v=5t-5t^2

5t-5t^2=0

t = 1 seconds

So, at t = 1 second the velocity of the particle is zero.

7 0
2 years ago
As the solar system formed, most of its mass became concentrated in one part of it. What is that that part?
sertanlavr [38]
That was sun as some smaller masses formed planets and other remaining formed sun
4 0
3 years ago
A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what is the y-component of the normal force?
Rama09 [41]

Answer:

The y-component of the normal force is 45.74 N.

Explanation:

Given that,

Mass of the crate, m = 5 kg

Angle with hill, \theta=21^{\circ}

We need to find the y component of the normal force. We know that the y component of the normal force is given by :

F_y=F\ \cos\theta\\\\F_y=mg\ \cos\theta\\\\F_y=5\times 9.8\ \cos(21)\\\\F_y=45.74\ N

So, the y-component of the normal force is 45.74 N. Hence, this is the required solution.

7 0
2 years ago
Blocks with masses of 3.0 kg, 4.0 kg, and 5.0 kg are lined up in a row on a frictionless table. All three are pushed forward by
exis [7]

Answer:

This is very hard bit I think 6.3 my, I'm not shure.

5 0
3 years ago
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