100 POINTS. PLEASE PROVIDE EXPLANATION
1 answer:
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Answer:
The spring has a constant of 126.334 newtons per meter.
Explanation:
Given that mass-spring system experiment a simple harmonic motion, the angular frequency of the system as a function of frequency is:
Where:
- Angular frequency, measured in radians per second.
- Frequency, measured in hertz.
Given that , the angular frequency of the system is:
Now, the angular frequency can be obtained in terms of spring constant and mass. That is:
Where:
- Spring constant, measured in newtons per meter.
- Mass, measured in kilograms.
The spring constant is now cleared:
If and
, the spring constant is:
The spring has a constant of 126.334 newtons per meter.
the potential at the center of curvature of the arc = v = Q ∕ (4πε∘a) or
ATQ,
We have density of charge,
λ =
Where L is the rod's length, in this case the semicircle's length L = πr
Q is the charge on the rod
The potential created at the center by an differential element of charge is:
where k is the coulomb's constant
r is the distance from dQ to center of the circle
v = ∫ , Where a = radius, k = 1 / 4πε∘
v = or Q ∕ (4πε∘a)
To learn more about potential from the given link
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