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3 years ago

explain y it is easier to loosen a tight but using a spanner with along handle than with a short handle

Physics

1 answer:

8090 [49]3 years ago

3 0

Answer:

This is because using a long handled requires less force to the center of gravity and makes it easier to rotate than a short handled spanner

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3 years ago

If you weighed 130 pounds on earth, you would weigh _____pounds on the moon

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Answer:

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3 years ago

When a person floating in swimming pool, they experience an upthrust. what causes this effect?

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3 years ago

An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec

aivan3 [116]

Answer:

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

$x = V*t = -8\frac{m}{s} *3s = -24m$

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

$v^2 = v_0^2 + 2a*d$

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

$d = \frac{v^2 - v_0^2}{2a} = \frac{(0m/s)^2 - (-8m/s)^2}{2*7m/s^2}= -4.57m$

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

$t_1 = \frac{v}{a} = \frac{8m/s}{7m/s^2} = 1.143 s$

Then, the time of the second phase will be:

$t_2 = 9s - t_1 = 9s - 1.143s = 7.857s$

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

$x = \frac{1}{2}a*t^2 + v_0*t + x_0$

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

$x = \frac{1}{2}*7\frac{m}{s^2}*t^2 + 0m/s*t + 0m = 216.07m$

So, the total distance covered by this object in meters will be the sum of all the distances we found:

$x_total = 24m + 4.57m + 216.07m = 244.64m$

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3 years ago

How far can a mother push a 20.0 kg baby carriage, using a force of 62 N, if she can only do 2920 J of work? (Round to include t

alexgriva [62]

The mathematical definition of work (W) is force (F) multiplied by distance (x). In order to determine the distance for fixed force and work the above equation needs to be rearranged to make x the subject. The work divided by the force is equal to the distance. In this case the mother can push the baby carriage by a distance equal to 2920 divided by 62, which is 47.1 metres.

5 0

3 years ago

explain y it is easier to loosen a tight but using a spanner with along handle than with a short handle​

explain y it is easier to loosen a tight but using a spanner with along handle than with a short handle