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Alecsey [184]
3 years ago
13

If the velocity of a 440 Hz sound is 1,265 ft/s in the air and 5,990 ft/s in seawater, find the wavelength of this sound in (a)

air and ft (b) seawater. Ft
Physics
1 answer:
NemiM [27]3 years ago
6 0

Answer:

hi I don't now but I have to do it to get in

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What air pollution is and its rate of spreading worldwide?
slavikrds [6]

Answer:

Air pollution is a mixture of solid particles and gases in the air. Car emissions, chemicals from factories, dust, pollen and mold spores may be suspended as particles. Ozone, a gas, is a major part of air pollution in cities. When ozone forms air pollution, it's also called smog.

7 0
2 years ago
Four point charges each having charge Q are located at the corners of a square having sides of length a.
Murljashka [212]

Answer:

Explanation:

Given

Four Point charges are Placed at the corner of a square with side length a

Length of diagonal a\sqrt{2}

Distance of charge from center \frac{a\sqrt{2}}{2}=\frac{a}{\sqrt{2}}

Potential at the center due to four charges is given by

V=\frac{4\cdot k\cdot Q}{\frac{a}{\sqrt{2}}}

as all the four charges are equal and placed symmetrical about center

Work done required to bring a fifth charge q from infinity to the center of the square

W=qV

W=\frac{4\sqrt{2}kQq}{a}    

7 0
3 years ago
How do prokaryotes differ from eukaryotes? How are they similar?
Sphinxa [80]
Prokaryotes differ from eukaryotes in their less complexity, lacking a nucleus. Eukaryotes are more complex organisms and have a nucleus. They are both similar because they are a type of organism and have membrane bound organelles.

7 0
2 years ago
When you lift an object by moving only your forearm, the main lifting muscle in your arm is the biceps. Suppose the mass of a fo
Sladkaya [172]

Answer:

The answers to the questions are;

The force the biceps must exert to hold a 850 g ball at the end of the forearm at distance dball = 34.0 cm from the elbow, with the forearm parallel to the floor is 166.77 N Upwards.

The force the elbow must  exert is 145.6785 N downwards.

Explanation:

We are required to analyze the system using the principle of moments as follows.

Mass of forearm = 1.30 kg

Weight of forearm = mass × acceleration due to gravity = 1.30 kg × 9.81  m/s²= 12.753 N

Location of point of action of weight of forearm = midpoint  17 cm

Forearm to biceps distance = 3.00 cm from the elbow.

Mass of the ball = 850 g

Weight of ball = mass × acceleration due  to gravity = 0.850 kg × 9.81 = 8.3385 N

Position of the ball = end of the forearm

Therefore, taking moment about the elbow, we have

∑Mₓ = 0, we take clockwise moment to be positive, therefore

8.3385 N× 34.0 cm + 12.753 N× 17 cm - F_{biceps}×3.00 cm = 0

Therefore F_{biceps}×3.00 cm = 500.31 N cm

Therefore F_{biceps} = (500.31 N·cm)/(3.00 cm) = 166.77 N Upwards

The force exerted by the elbow is given by,

Taking moment about the point of contact between the biceps and the forearm, we get

F_{elbow} × 3.00 cm = 8.3385 N× 31.0 cm + 12.753 N× 14 cm

F_{elbow} = 145.6785 N downwards.

4 0
2 years ago
4. How much mass is required to exert a force of 25 Newtons, accelerating at 5 m/s?
lions [1.4K]
F = ma
F/a = m
(25 N) / (5 m/s2) = m
4 kg = m
8 0
3 years ago
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