An ampere (AM-pir), or amp
Answer:
v = 15.65 m/s
Explanation:
We use conservation of mechanical energy between initial (i) and final (f) states:
Pi + KEi = Pf + KEf
At the top of the cave at the instant the bat starts to fall, there is only potential energy since the bat's velocity is zero.
Pi = m g h = 600 J
and the KEi = 0 J (no velocity)
Knowing the height of the cave's roof (12.8 m) , we can find the mass of the bat:
m = 600 J / (g 12.5) = 4.9 kg
Using conservation of mechanical energy, the final state is:
Pf + KEf = 600 J
with Pf = 0 (just touching the ground)
KEf= 1/2 4.9 (v^2)
and we solve for the velocity:
600 J = 0 + 1/2 4.9 (v^2)
v^2 = 600 * 2 / 4.9 = 244.9
v = 15.65 m/s
Answer:
270 m/s²
Explanation:
Given:
α = 150 rad/s²
ω = 12.0 rad/s
r = 1.30 m
Find:
a
The acceleration will have two components: a radial component and a tangential component.
The tangential component is:
at = αr
at = (150 rad/s²)(1.30 m)
at = 195 m/s²
The radial component is:
ar = v² / r
ar = ω² r
ar = (12.0 rad/s)² (1.30 m)
ar = 187.2 m/s²
So the magnitude of the total acceleration is:
a² = at² + ar²
a² = (195 m/s²)² + (187.2 m/s²)²
a = 270 m/s²
The concept required to solve this problem is linked to inductance. This can be defined as the product between the permeability in free space by the number of turns squared by the area over the length. Recall that Inductance is defined as the opposition of a conductive element to changes in the current flowing through it. Mathematically it can be described as
![L = \frac{\mu N^2 A}{l}](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7B%5Cmu%20N%5E2%20A%7D%7Bl%7D)
Here,
= Permeability at free space
N = Number of loops
A = Cross-sectional Area
l = Length
Replacing with our values we have,
![L = \frac{(4\pi *10^{-7})(153)^2(\pi (\frac{5.11*10^{-3}}{2})^2)}{2.47*10^{-2}}](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7B%284%5Cpi%20%2A10%5E%7B-7%7D%29%28153%29%5E2%28%5Cpi%20%28%5Cfrac%7B5.11%2A10%5E%7B-3%7D%7D%7B2%7D%29%5E2%29%7D%7B2.47%2A10%5E%7B-2%7D%7D)
![L = 0.00002442H](https://tex.z-dn.net/?f=L%20%3D%200.00002442H)
![L = 24.42\mu H](https://tex.z-dn.net/?f=L%20%3D%2024.42%5Cmu%20H)
Therefore the Inductance is ![24.42\mu H](https://tex.z-dn.net/?f=24.42%5Cmu%20H)
Answer: 20
Explanation: Mass number is the number of neutrons plus the number of protons. 8 + 12 gives 20.