Which of the following are examples of chemical energy being released or stored?

A ray of light contains two colors: red with wavelength of 660 nm and blue with wavelength 470 nm. The ray passes through two na

densk [106]

Answer:

The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.

Explanation:

Given that,

Wavelength of red = 660 nm

Wavelength of blue = 470 nm

Separated d= 0.30 mm

Distance between screen and slits D= 5.0 m

We need to calculate the distance for red wavelength

Using formula for distance

$y=\dfrac{\lambda D}{d}$

Where, D = distance between screen and slits

d = separation of slits

Put the value into the formula

$y=\dfrac{660\times10^{-9}\times5.0}{0.30\times10^{-3}}$

$y=11\ mm$

For blue wavelength,

Put the value into the formula again

$y'=\dfrac{470\times10^{-9}\times5.0}{0.30\times10^{-3}}$

$y'=7.83\ mm$

We need to calculate the distance on the screen between the first-order bright fringes for each wavelength

Using formula for distance

$\Delta y=y-y'$

$\Delta y=11-7.83$

$\Delta y=3.17\ mm$

Hence, The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.

4 0

4 years ago

Suppose you are asked to find the amount of time t, in seconds, it takes for the turntable to reach its final rotational speed.

Annette [7]

Answer:

option (D)

Explanation:

Here initial rotation speed is given, final rotation speed is given and asking for time.

If we use

A) θ=θ0+ω0t+(1/2)αt2

For this equation, we don't have any information about the value of angular displacement and angular acceleration, so it is not useful.

B) ω=ω0+αt

For this equation, we don't have any information about angular acceleration, so it is not useful.

C) ω2=ω02+2α(θ−θ0)

In this equation, time is not included, so it is not useful.

D) So, more information is needed.

Thus, option (D) is true.

5 0

3 years ago

At which angles relative to the centerline perpendicular to the doorway will someone outside the room hear no sound? Use 344 m/s

Leto [7]

Answer:

Angle = 0.2520 radians

Explanation:

Complete question:

Sound with frequency 1220Hz leaves a room through a doorway with a width of 1.13m . At what minimum angle relative to the centerline perpendicular to the doorway will someone outside the room hear no sound? Use 344m/s for the speed of sound in air and assume that the source and listener are both far enough from the doorway for Fraunhofer diffraction to apply. You can ignore effects of reflections.

Given Data:

Speed of sound =v= 344 m/sec ;

Width of doorway =d= 1.13m ;

Frequency of sound =f= 1220 Hz ;

Solution:

As we know that

Wvelength = w = v/f = 344/1220 = 0.281967m

Now we also know that

w = dsin(A) where A is the angle

A = arcsin(w/d) =14.44° = 14.44*(3.14/180) = 0.2520 radians

At the angle of 0.252 radians relative to the centreline perpendicular to the doorway a person outside the room will hear no sound under given conditions.

4 0

4 years ago

heeelllllpppp plleeeaaassseee

Verdich [7]

$\underbrace{\sf{Elementary~ charge} }$

Explanation:

We call the magnitude of the charge of an electron as ELEMENTARY CHARGE.

6 0

3 years ago

Read 2 more answers

A 70 n force pulls a box straight up 5 m above the ground. how much work is done on the box?

lord [1]

The work done on the box is 350 joules

Workdone can be described as the amount of energy transferred from an object.

Force can be described as the push on an object, this push makes the object to go through a change in velocity.

Distance can be described as the movement of an object towards any given direction.

It can be calculated by multiplying the force by the distance

Workdone= force × distance

= 70 × 5

= 350

Thus, the work done on the box is 350 joules

Please see the link below for more information
brainly.com/question/14330400?referrer=searchResults

#SPJ1

6 0

2 years ago