Answer:
323 m/s²
Explanation:
Given:
x₀ = 0 m
y₀ = 0 m
x = 29500 cos 65°
y = 29500 sin 65°
v₀x = 1810 cos 20°
v₀y = 1810 sin 20°
t = 9.20
Find:
ax, ay, θ
First, in the x direction:
x = x₀ + v₀ t + ½ at²
29500 cos 32° = 0 + (1810 cos 20°) (9.20) + ½ ax (9.20)²
25017 = 15648 + 42.32 ax
ax ≈ 221.4
And in the y direction:
y = y₀ + v₀ t + ½ at²
29500 sin 32° = 0 + (1810 sin 20°) (9.20) + ½ ay (9.20)²
15633 = 5695 + 42.32 ay
ay ≈ 234.8
Therefore, the magnitude of the acceleration is:
a² = ax² + ay²
a² = (221.4)² + (234.8)²
a ≈ 322.7
Rounded to 3 significant figures, the magnitude of the acceleration is approximately 323 m/s².
Answer:
A north magnet attracts a south magnet
Explanation:
The opposite polar magnetic field will attract each other while the same polar magnetic fields will repel each other.
Answer:
t=62 s
Explanation:
Applying the conservation of linear momentum formula:
the initial velocity is zero, we can calculate the man's mass using the gravitational force formula:
now:
That is 0.13m/s due south.
because there is no friction, the man will maintain a constant velocity, so:
The distance is 1760 km
The speed is 960 km hour I.e 960 divide by 60 = 16 km/minute
hence in time 1 hour 50 minutes I.e 110 minutes
distance travelled is 110 - 16 = 1760 km
Answer:
3.61 m/s²
Explanation:
Given:
v = 12 m/s
x = 7 m
x₀ = 0 m
t = 6 s
Find:
a
x = x₀ + vt - ½ at²
7 m = 0 m + (12 m/s) (6 s) - ½ a (6 s)²
a = 3.61 m/s²
